unordered_map<string, vector<string>>letters{//声母--韵母 组合{"B",{"a","o","i","u","ai","ei","ao","iao","ie","an","ian","en","in","ang","eng","ing"}}, {"P",{"a","o","i","u","ai","ei","ao","iao","ou","ie","an","ian","en","in","ang","...
unordered_map<int, string> mymap; (2)使用n个元素构造unordered_map: unordered_map<int, string> mymap = {{1, "one"}, {2, "two"}, {3, "three"}}; (3)使用给定的范围构造unordered_map: 1 vector<pair<int, string>> myVector = {{1, "one"}, {2, "two"}, {3, "three"}};...
unordered_map<string, vector<string>>letters{//声母--韵母 组合{"B",{"a","o","i","u","ai","ei","ao","iao","ie","an","ian","en","in","ang","eng","ing"}}, {"P",{"a","o","i","u","ai","ei","ao","iao","ou","ie","an","ian","en","in","ang","...
unordered_map classMyclass{public:intindex;Myclass(){index=0;};Myclass(constMyclass&other){index=other.index;};Myclass(Myclass&&other)noexcept:index(other.index){std::cout<<other.index<<std::endl;// will be called here if no reserveother.index=0;};// needed by unordered_mapbooloperato...
在模拟实现中,我的my_unordered_set和my_unordered_map封装了一个哈希表HashTable,但set里面存的是一个数据K,而set里面存的是pair<K,T>,HashTable里面只接受一个data,这就导致了如果是set,data就是K类型,如果是map,data就是pair<K,V>,但我们只有一个哈希表,该怎么解决这种矛盾呢?
vector<string>now; //unordered_map<string, vector<string>>myhash; unordered_map<string, vector<string>>::iterator it; for (int i =0;i <str.size();i++) { temp = str[i]; sort(temp.begin(), temp.end()); now.clear();
这四个容器与红黑树结构的关联式容器使用方式基本类似,只是 其底层结构不同,他们不再以红黑树作为底层结构,而是以挂哈希桶的哈希表作为底层结构,就是用存储结点指针的vector来实现哈希表,哈希表的每个位置是一个桶,桶结构是一个存储value的单链表,unordered_set的桶中结点存储的是一个key值,unordered_map的桶中...
#include <unordered_map> #include <vector> using namespace std; struct Vertex { string key; // key of the vertex. vector<string> adj; // keys of adjacent vertices. vector<double> weights; // weights of edges to adjacent vertices. ...
unordered_map也是无序的。 1unordered_map是存储键值对的关联式容器,其允许通过keys快速的索引到与其对应的value。 2在unordered_map中,键值通常用于惟一地标识元素,而映射值是一个对象,其内容与此键关联。键和映射值的类型可能不同。 3在内部,unordered_map没有对按照任何特定的顺序排序, 为了能在常数范围内找到...
unordered_map<int, string> myMap; for(auto& pair : myMap) { // 使用 pair.first 和 pair.second 访问键值对 } 复制代码避免频繁拷贝:在遍历unordered_map时,如果需要修改值,应该使用引用或指针避免频繁拷贝。unordered_map<int, vector<int>> myMap; for(auto& pair : myMap) { vector<int>& ...