unordered_map<string, vector<string>>letters{//声母--韵母 组合{"B",{"a","o","i","u","ai","ei","ao","iao","ie","an","ian","en","in","ang","eng","ing"}}, {"P",{"a","o","i","u","ai","ei","ao","iao","ou","ie","an","ian","en","in","ang","...
unordered_map<string, vector<string>>letters{//声母--韵母 组合{"B",{"a","o","i","u","ai","ei","ao","iao","ie","an","ian","en","in","ang","eng","ing"}}, {"P",{"a","o","i","u","ai","ei","ao","iao","ou","ie","an","ian","en","in","ang","...
#include<iostream>#include<map>#include<unordered_map>#include<chrono>#include<string>#include<vector>#include<random>// 计时辅助函数template<typenameFunc>longlongtimeOperation(Func func){autostart = std::chrono::high_resolution_clock::now();func();autoend = std::chrono::high_resolution_clock::...
从unordered_map获取键和值的列表(以vector形式)的最有效方法是什么具体来说,假设所讨论的映射是一个unordered_map<string, double>。然后,我希望以vector<string>的形式获取密钥,以vector<double>的形式获取值。unordered_map<string, 浏览5提问于2011-12-13得票数 75 回答已采纳 3回答 基于最高值从数组中获...
unordered_map class Myclass { public: int index; Myclass() { index = 0; }; Myclass(const Myclass& other) { index = other.index; }; Myclass(Myclass&& other) noexcept : index(other.index) { std::cout << other.index << std::endl; // will be called here if no reserve other....
4. unordered_map的[]访问 在unordered_map的使用介绍中,我们知道可以用[]来访问修改键值对以及插入数据: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 //迭代器构造 std::vector<pair<string, string>> v = { {"上", "up"}, { "下", "down"}, { "左", "left"}, { "右", "...
unordered_map<int, string> myMap; for(auto& pair : myMap) { // 使用 pair.first 和 pair.second 访问键值对 } 复制代码避免频繁拷贝:在遍历unordered_map时,如果需要修改值,应该使用引用或指针避免频繁拷贝。unordered_map<int, vector<int>> myMap; for(auto& pair : myMap) { vector<int>& ...
vector<string>now; //unordered_map<string, vector<string>>myhash; unordered_map<string, vector<string>>::iterator it; for (int i =0;i <str.size();i++) { temp = str[i]; sort(temp.begin(), temp.end()); now.clear();
class Solution { public: vector<vector<string>> groupAnagrams(vector<string>& strs) { unordered_map<string,vector<string>> map; vector<vector<string>> result; for(auto& str:strs) { string key = str; sort(key.begin(),key.end()); map[key].emplace_back(str); } for(auto m:map) ...
1.1 vector(数组)封装动态数组的顺序容器。 at():所需元素值的引用。 front():访问第一个元素(返回引用)。 back():访问最后一个元素(返回引用)。 beign():返回指向容器第一个元素的迭代器。 end():返回指向容器末尾段的迭代器。 empty():检查容器是否为空。