Given the root of a binary tree, check whether it is a mirror of itself (i.e., symmetric around its center). Example 1: Input: root = [1,2,2,3,4,4,3] Output: true Example 2: Input: root = [1,2,2,null,3,null,3] Output: false 1.2 中文描述 给你一个二叉树,你要判断它是...
* TreeNode(int x) : val(x), left(NULL), right(NULL) {} * };*/classSolution {public:boolisSymmetric(TreeNode *root) {if(!root)returntrue;if(!root -> left && !root -> right)returntrue;if( (!root -> left && root -> right) || (root -> left && !root -> right) )returnf...
1/**2* Definition for binary tree3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x; }8* }9*/10publicclassSolution {11publicbooleanisSymmetric(TreeNode root) {12if(root ==null)returntrue;13returncheck(root.left, root.right);1...
} return isSameTree(root.left, root.right); } public boolean isSameTree(TreeNode p, TreeNode q) { if (p == null || q == null) { return p == q; } boolean f = p.val == q.val; boolean f2 = isSameTree(p.left, q.right); boolean f3 = isSameTree(p.right, q.left); ...
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题目描述 Given a binary tree, check whether it is a mirror of itself (ie, symmetric around ...
For example, this binary tree[1,2,2,3,4,4,3]is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following[1,2,2,null,3,null,3]is not: 1 / \ 2 2 \ \ 3 3 My code: /** * Definition for a binary tree node. ...
[LeetCode] Symmetric Tree For example, this binary tree is symmetric: 代码语言:javascript 代码 /\22\/\34 But the following is not: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 1/\22\ \33 翻译: 给定一颗二叉树,检查它是否与自己的镜像是同一棵树(围绕根节点对称)...
1#Definition for a binary tree node2#class TreeNode:3#def __init__(self, x):4#self.val = x5#self.left = None6#self.right = None78classSolution:9#@param root, a tree node10#@return a boolean11defisSymmetric(self,root):12ret =True13q =[]14s =[]15ifroot != None:#注意root...
Can you solve this real interview question? Symmetric Tree - Given the root of a binary tree, check whether it is a mirror of itself (i.e., symmetric around its center). Example 1: [https://assets.leetcode.com/uploads/2021/02/19/symtree1.jpg] Inpu