For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees ofeverynode never differ by more than 1. 解题思路1(下面给出两种代码实现,代码1和代码2):采用递归的方法,对每一层的节点进行遍历,从叶子节点开始回溯,并从下往上判断每一层的各个...
TreeNode rightChild;intvalue;publicTreeNode(intvalue){this.value=value; }publicTreeNode(){ } }publicstaticvoidmain(String[] args){ BalancedBinaryTree balancedBinaryTree =newBalancedBinaryTree();char[] arr0 =newchar[]{'#'};char[] arr1 =newchar[]{'3','9','2','#','#','1','7'}...
Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example 1: Given the following tree [3,9,20,null,null,15,7]: ...
Can you solve this real interview question? Balanced Binary Tree - Given a binary tree, determine if it is height-balanced. Example 1: [https://assets.leetcode.com/uploads/2020/10/06/balance_1.jpg] Input: root = [3,9,20,null,null,15,7] Output: tru
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 题目分析: 平衡二叉树:(1)要么为空,要么左右子树的深度差值不超过1;(2)左右两个子树都是一棵平衡二叉树,即子树也都要都满足条件(1...
平衡二叉树 - 力扣(LeetCode)leetcode-cn.com/problems/balanced-binary-tree/ 题目描述 给定一个二叉树,判断它是否是高度平衡的二叉树。 本题中,一棵高度平衡二叉树定义为: 一个二叉树每个节点 的左右两个子树的高度差的绝对值不超过1。 示例1: 给定二叉树 [3,9,20,null,null,15,7] 3 / \ 9 ...
leetcode -- Balanced Binary Tree -- 简单重点 https://leetcode.com/problems/balanced-binary-tree/ 求depth,recursive就行 class Solution(object): def depth(self, root): if not root: return 0 return max(self.depth(root.left), self.depth(root.right)) + 1...
LeetCode 110. Balanced Binary Tree 简介:给定一颗二叉树,判断此树是不是平衡二叉树.平衡二叉树的条件是:当前节点的左右子树高度差不超过1,且左右子树都是平衡二叉树. Description Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as:...
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For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 利用求最大深度,然后再求两边相减的绝对值如果是小于1的就行,然后如果所有子树都是平衡二叉树那么大树那必然是平衡二叉树。