* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isBalanced(TreeNode *root) { if(!root)return true; int root_left=0,root_right...
classSolution2 {public:boolisBalanced(TreeNode*root) {if(root==NULL){returntrue; }intheight=getheight(root);if(height==-1){returnfalse; }returntrue; }intgetheight(TreeNode *root){if(root==NULL){return0; }intlleft=getheight(root->left);inttrigth=getheight(root->right);if(lleft==-1...
LeetCode 110 Balanced Binary Tree(平衡二叉树)(*) 翻译 (高度是名词不是形容词…… 对于这个问题。一个高度平衡二叉树被定义为: 这棵树的每一个节点的两个子树的深度差不能超过1。 原文 分析 这道题。我觉得非常有意义,考察得也非常全面。我觉得的主要是有以下几个方面: 先从小的模块開始写。也就是树的...
package leetcode /** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ func isBalanced(root *TreeNode) bool { if root == nil { return true } leftHight := depth(root.Left) rightHight := depth(root.Right) retur...
LeetCode 110. Balanced Binary Tree Description Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as: a binary tree in which the depth of the two subtrees of every node never differ by more than 1. Example 1: Given the ...
Can you solve this real interview question? Balanced Binary Tree - Given a binary tree, determine if it is height-balanced. Example 1: [https://assets.leetcode.com/uploads/2020/10/06/balance_1.jpg] Input: root = [3,9,20,null,null,15,7] Output: tru
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isBalanced(TreeNode root) { if (root == null) { ...
思路:https://leetcode.com/problems/balanced-binary-tree/discuss/35691/The-bottom-up-O(N)-solution-would-be-better.左右子树的高度差不能超过1。 工程代码下载 /** * Definition for a binary tree node. * struct TreeNode { * int val;
LeetCode—110. Balanced Binary Tree 题目 https://leetcode.com/problems/balanced-binary-tree/description/ 判断一棵二叉树是否是平衡二叉树。 平衡二叉树指的是,两棵子树的任一节点的深度相差不超过1. 思路及解法 首先写一个函数用来得到每一个子树的深度,然后递归调用原函数,判断两棵子树的深度差... ...
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { private: bool checkBalanced(TreeNode *node, int &depth) ...