publicclassCheckTreeBalanced2 {publicintcheckHeight(TreeNode root){if(root ==null){return0; }intleftHeight =checkHeight(root.left);if(leftHeight == -1){return-1; }intrightHeight =checkHeight(root.right);if(rightHeight == -1){return-1; }intheightDiff = leftHeight -rightHeight;if(Math....
*/classSolution{publicbooleanisBalanced(TreeNode root){returncheckDepth(root) != -1; }intcheckDepth(TreeNode root){if(root ==null) {return0; }intleft=checkDepth(root.left);if(left == -1) {return-1; }intright=checkDepth(root.right);if(right == -1) {return-1; }if(Math.abs(left...
For this problem, a height-balanced binary tree is defined as:a binary tree in which the left and right subtrees of every node differ in height by no more than 1. 英文版地址 leetcode.com/problems/b 中文版描述 给定一个二叉树,判断它是否是高度平衡的二叉树。本题中,一棵高度平衡二叉树定义...
Given a binary tree, determine if it is height-balanced. For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 题目分析: 平衡二叉树:(1)要么为空,要么左右子树的深度差值不超过1;(2)...
https://leetcode.com/problems/balanced-binary-tree/ 题目: Given a binary tree, determine if it is height-balanced. every 思路: 根据结点高度,递归判断是否满足平衡树定义。此题跟Kth Smallest Element in a BST做法类似,在遍历过程中遇到满足某条件的结点时,将结果放到全局变量中,如果没遇到最终递归返回的...
0110 Balanced Binary Tree Go 48.1% Easy 0111 Minimum Depth of Binary Tree Go 43.5% Easy 0112 Path Sum Go 47.6% Easy 0113 Path Sum II Go 56.5% Medium 0114 Flatten Binary Tree to Linked List Go 61.0% Medium 0115 Distinct Subsequences Go 43.7% Hard 0116 Populating Next Right Pointe...
110Balanced Binary TreePythonRecursion 1. Top-down O(n^2) and O(n), Bottom-up recursion with sentinel -1 O(n) and O(n) 111Minimum Depth of Binary TreePython1. Recursion, note that when size of left (ld) or right (rd) is 0, then min = 1 + ld + rd ...
// Solution 1: Split in half, reverse one, check for a match. 代码1 //Code 1 235 Lowest Common Ancestor of a Binary Search Tree // #235二叉搜索树最近公共祖先 描述:如题。 //#235Description: Lowest Common Ancestor of a Binary Search Tree | LeetCode OJ ...
* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */publicclassSolution{publicbooleanisBalanced(TreeNoderoot){if(root==null){returntrue;}intret=helper(root);returnret==-1?false:true...
Given a binary tree, determine if it is height-balanced. a binary tree in which the depth of the two subtrees of every node never differ by more than 1. 判断一个二叉树是否为平衡二叉树 关键: 1 平衡二叉树的每一个节点的子数深度相差小于1 ...