left(NULL), right(NULL) {}8* };9*/10/*常规层序遍历思想,每层入队结束压入一个空节点,作为标志*/11classSolution {12public:13vector<vector<int> > levelOrder(TreeNode *root) {14vector<vector<int>> vec_vec_tree;//创建空vector,存放最后返回的遍历二叉树的
#Definition for a binary tree node.#class TreeNode(object):#def __init__(self, x):#self.val = x#self.left = None#self.right = None"""利用堆栈先进后出的特点"""classSolution(object):defpreorderTraversal(self, root):""":type root: TreeNode :rtype: List[int]"""result=[] slack=...
LeetCode 106. Construct Binary Tree from Inorder and Postorder Traversal Description Given inorder and postorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given inorder = [9,3,15,20,7]postorder = [9,15,7...
LeetCode Top 100 Liked Questions 543. Diameter of Binary Tree (Java版; Easy) 题目描述 Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or...
LeetCode Top 100 Liked Questions 105. Construct Binary Tree from Preorder and Inorder Traversal (Java版; Medium) 题目描述 Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. ...
LeetCode 105. Construct Binary Tree from Preorder and Inorder Traversal Description Given preorder and inorder traversal of a tree, construct the binary tree. Note: You may assume that duplicates do not exist in the tree. For example, given ...
Can you solve this real interview question? Lowest Common Ancestor of a Binary Tree - Given a binary tree, find the lowest common ancestor (LCA) of two given nodes in the tree. According to the definition of LCA on Wikipedia [https://en.wikipedia.org/wi
图片来源:https://leetcode.com/articles/binary-tree-right-side-view/ 对于时间复杂度来说,基本上都是O(n),因为要访问所有的点。 对于空间复杂度来说,BFS取决于扫描过程中每层的node数,就是树的宽度,而DFS取决于扫描过程中树的深度。最坏情况两个都是O(n)。
今天介绍的是LeetCode算法题中Easy级别的第124题(顺位题号是543)。给定二叉树,您需要计算树的直径长度。 二叉树的直径是树中任意两个节点之间最长路径的长度。 此路径可能会也可能不会通过根节点。例: 给出一棵二叉树 1 / \ 2 3 / \ 4 5 返回3,这是路径[4,2,1,3]或[5,2,1,3]的长度。 注意:...
int toNode (在 correctBinaryTree 中不可见) 当以root 为根的二叉树被解析后,值为 fromNode 的节点 TreeNode 将其右子节点指向值为 toNode 的节点 TreeNode 。然后, root 传入 correctBinaryTree 的参数中。 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/correct-a-binary-tree ...