其实题目的意思就是相当于二叉树每一行的最右边的一个元素,那么简单,先bfs后取每一个数组的最后一位数就可以了,代码如下: 1/**2* Definition for a binary tree node.3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NU...
英文网站:199. Binary Tree Right Side View 中文网站:199. 二叉树的右视图 问题描述 Given therootof a binary tree, imagine yourself standing on theright sideof it, returnthe values of the nodes you can see ordered from top to bottom. Example 1: Input: root = [1,2,3,null,5,null,4] O...
TreeNode*node =q.front(); q.pop();if(node->left) q.push(node->left);if(node->right) q.push(node->right); } }returnres; } }; LeetCode All in One 题目讲解汇总(持续更新中...)
【leetcode】Binary Tree Right Side View(middle) Given a binary tree, imagine yourself standing on therightside of it, return the values of the nodes you can see ordered from top to bottom. For example: Given the following binary tree, 1 <--- / \ 2 3 <--- \ \ 5 4 <--- 1. ...
http://www.programcreek.com/2014/04/leetcode-binary-tree-right-side-view-java/ 看了这篇博客就懂了。 ** 总结: queue来遍历tree ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { ...
Top-View-of-a-Tree 入选理由 暂无 题目地址 https://binarysearch.com/problems/Top-View-of-a-Tree 前置知识 BFS 哈希表 题目描述 本题和 987. 二叉树的垂序遍历 类似。 因此大家也可以用 987. 二叉树的垂序遍历 来打卡。(因为 binarysearch 现在 down 掉了,可能打不了卡) Given a binary tree root,...
packageleetcodeimport("github.com/halfrost/LeetCode-Go/structures")// TreeNode definetypeTreeNode=structures.TreeNode/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } ...
Blogger:https://blog.baozitraining.org/2019/10/leetcode-solution-199-binary-tree-right.html Youtube:https://youtu.be/_g6pN64bF-o 博客园: https://www.cnblogs.com/baozitraining/p/11595617.html B站: https://www.bilibili.com/video/av69112013/ ...
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