left,root.right); } public static boolean helper(TreeNode left,TreeNode right){ if(left == null && right == null){ return true; } if((left != null && right == null) || (left == null && right != null)){ return false; } if(left.value != right.value){ return false; } ...
classSolution {public:boolisSymmetric(TreeNode *root) {if(root == NULL)returntrue; stack<TreeNode *>s; s.push(root->left); s.push(root->right);while(!s.empty()){ TreeNode*r =s.top();s.pop(); TreeNode*l =s.top();s.pop();if(r == NULL && l == NULL)continue;//this i...
1/**2* Definition for binary tree3* public class TreeNode {4* int val;5* TreeNode left;6* TreeNode right;7* TreeNode(int x) { val = x; }8* }9*/10publicclassSolution {11publicbooleanisSymmetric(TreeNode root) {12if(root ==null)returntrue;13returncheck(root.left, root.right);1...
import java.util.Queue; /*class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } } */ public class Solution { public boolean isSymmetric(TreeNode root) { if(root==null) return true; Queue<TreeNode> myQueue = new LinkedList<>(); myQueue.add(root...
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#LeetCode# I have solved Symmetric Tree. Come and join the fun! http://t.cn/RUsuCVV
101. 对称二叉树 - 给你一个二叉树的根节点 root , 检查它是否轴对称。 示例 1: [https://pic.leetcode.cn/1698026966-JDYPDU-image.png] 输入:root = [1,2,2,3,4,4,3] 输出:true 示例 2: [https://pic.leetcode.cn/1698027008-nPFLbM-image.png] 输入:ro
101. 对称二叉树 - 给你一个二叉树的根节点 root , 检查它是否轴对称。 示例 1: [https://pic.leetcode.cn/1698026966-JDYPDU-image.png] 输入:root = [1,2,2,3,4,4,3] 输出:true 示例 2: [https://pic.leetcode.cn/1698027008-nPFLbM-image.png] 输入:ro
101. Symmetric Tree 题目 给定一个二叉树的根root,检查它是否是自身的镜像。 解析 判断左子树和右子树是否相等。 (1)非空节点,加入其左右子树,并叠加该层左右子树的非空元素个数 (2)空节点,设其左右子树为空 issym(left, right) bool 伪代码 ifleft==nil&&right==nilreturntrueifleft==nil||right==nil...
给定二叉树,检查它是否是自身的镜像(即,围绕其中心对称)。 For example, this binary tree[1,2,2,3,4,4,3]is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 But the following[1,2,2,null,3,null,3]is not: 1 / \ 2 2 \ \ 3 3 ...