#Definition for a binary tree node.#class TreeNode:#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution:defisSymmetric(self, root: TreeNode) ->bool:ifroot ==None:returnTruedefismirror(root1,root2):ifroot1 == Noneandroot2 ==None:returnTrueelifroo...
AC代码(Python) 1#Definition for a binary tree node.2#class TreeNode(object):3#def __init__(self, x):4#self.val = x5#self.left = None6#self.right = None78classSolution(object):9defisSymmetric(self, root):10"""11:type root: TreeNode12:rtype: bool13"""14defhelp(p, q):15ifp...
Binary Tree Tilt (Python) 36 -- 4:58 App Leetcode 476. Number Complement (Python) 24 -- 5:53 App Leetcode 1200. Minimum Absolute Difference (Python) 24 -- 5:10 App Leetcode 849. Maximize Distance to Closest Person (Python) 83 -- 5:16 App LeetCode 795. Number of Subarrays...
1#Definition for a binary tree node2#class TreeNode:3#def __init__(self, x):4#self.val = x5#self.left = None6#self.right = None78classSolution:9#@param root, a tree node10#@return a boolean11defisSymmetric(self,root):12ret =True13q =[]14s =[]15ifroot != None:#注意root...
10 class Solution { 11 public: 12 bool isSymmetric(TreeNode *root) { 13 if(!root) 14 return true; //无根结点 15 else if(root->left==(void*)0 && root->right==(void*)0) //只有根结点的树 16 return true; 17 else if(root->left!=(void*)0 && root->right!=(void*)0 && isSy...
TreeNode(int x) { val = x; } } */ public class Solution { public boolean isSymmetric(TreeNode root) { if(root==null) return true; Queue<TreeNode> myQueue = new LinkedList<>(); myQueue.add(root); while(myQueue.isEmpty()==false) ...
* TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */classSolution{public:booldfs(TreeNode*t1,TreeNode*t2){if(!t1||!t2){if(!t1&&!t2)returntrue;returnfalse;}if(t1->val!=t2->val)returnfalse;returndfs(t1->left,t2->right)&&dfs(t1->right,t2-...
Python实现: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # Definition for a binary tree node. # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: def isSymmetric(self, root): """ :type root: TreeNode :rtype...
LeetCode 101. Symmetric Tree https://leetcode.com/problems/symmetric-tree/ Description Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree [1,2,2,3,4,4,3] i......
LeetCode—101. Symmetric Tree LeetCode—101. Symmetric Tree 题目 https://leetcode.com/problems/symmetric-tree/description/ 判断一棵二叉树是否是镜像的。 思路及解法 同样,有递归的方法和非递归的方法。非递归使用一个双向对列实现。 这里多说两句,虽然非递归的方法效率不是很高,在做树的题目的时候还是在...