思路:二叉树问题,考虑使用递归算法,计算出每一层的所有元素值 #Definition for a binary tree node.#class TreeNode:#def __init__(self, x):#self.val = x#self.left = None#self.right = NoneclassSolution:deflevelOrderBottom(self, root: TreeNode) ->List[List[int]]:ifroot == None:return[]...
* Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: bool isSameTree(TreeNode *p, TreeNode *q) { if(!p&&!q) return true; if(!p&&q...
来自专栏 · 山海(LeetCode) 1 人赞同了该文章 一、题目描述 给定两个二叉树,编写一个函数来检验它们是否相同。 如果两个树在结构上相同,并且节点具有相同的值,则认为它们是相同的。 示例 1: 输入: 1 1 / \ / \ 2 3 2 3 [1,2,3], [1,2,3] 输出: true 示例 2: 输入: 1 1 / \ 2 2 [...
一. 题目描写叙述 Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. 二. 题目分析 题目的意思非常easy,推断两棵树是否同样,递归,对两棵树的结点进行比較就可以。
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center). For example, this binary tree is symmetric: 1 / \ 2 2 / \ / \ 3 4 4 3 1. 2. 3. 4. 5. But the following is not: 1
题目链接[https://leetcode-cn.com/problems/same-tree/]tag: Easy; DFS; BFS; question: Given ...
Q100 Same Tree Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input:11/\/\2323[1,2,3],[1,2,3]Output:true...
Given the roots of two binary treespandq, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical, and the nodes have the same value. Example 1: Input:p = [1,2,3], q = [1,2,3]Output:true ...
asked in today's leetcode contest weekly contest 361 →Reply Gwynbleidd_ 20 months ago,#^| 0 you can select an edge and increase or decrease its weight by 1. If you are talking about today's leetcode contest question 4 then you read the question wrong. You can change the weight of...
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