1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12voidrecoverTree(TreeNode *root) {13//IMPORTANT: Please reset any member data y...
1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12voidrecoverTree(TreeNode *root) {13n1 = n2 = pre =NULL;14inorder(root);15...
publicvoidrecoverTree(TreeNoderoot){if(root==null)return;ArrayList<TreeNode>pre=newArrayList<TreeNode>();pre.add(null);ArrayList<TreeNode>res=newArrayList<TreeNode>();helper(root,pre,res);if(res.size()>0){inttemp=res.get(0).val;res.get(0).val=res.get(1).val;res.get(1).val=temp;...
Recover Binary Search Tree leetcode java https://leetcode.com/problems/recover-binary-search-tree/discuss/32535/No-Fancy-Algorithm-just-Simple-and-Powerful-In-Order-Traversal 描述 解析 解决方法是利用中序遍历找顺序不对的两个点,最后swap一下就好。 因为这中间的错误是两个点进行了交换,所以就是大的跑...
publicvoidrecoverTree2(TreeNoderoot){if(root==null){return;}//寻找左子树中最大的节点TreeNodemaxLeft=getMaxOfBST(root.left);//寻找右子树中最小的节点TreeNodeminRight=getMinOfBST(root.right);if(minRight!=null&&maxLeft!=null){//左边的大于根节点,右边的小于根节点,对应情况 3,左右子树中的两...
* Definition for a binary tree node.* struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void recoverTree(TreeNode* root) { ...
We run a preorder depth-first search (DFS) on therootof a binary tree. At each node in this traversal, we outputDdashes (whereDis the depth of this node), then we output the value of this node. If the depth of a node isD, the depth of its immediate child isD + 1. The depth...
Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure.Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 这个题我看到的想法是先把所有element in order走一遍,然后存进O(n) spa...
Two elements of a binary search tree (BST) are swapped by mistake.Recover the tree without changing its structure. publicvoidrecoverTree(TreeNoderoot){ArrayList<TreeNode>ary=newArrayList<TreeNode>();infixOrder(root,ary);TreeNodeerrorNodeAry[]=newTreeNode[2];intindex=-1;for(inti=0;i<ary.siz...
LintCode 691. Recover Binary Search Tree Recover Binary Search Tree 中文English In a binary search tree, (Only) two nodes are swapped. Find out these nodes and swap them. If there no node swapped, return original root of tree. Example...