publicTreeNode searchBST(TreeNode root, intval) {if(root ==null|| root.val==val) {returnroot; } Queue<TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root);while(!queue.isEmpty()) { TreeNode temp = queue.poll();if(temp.val==val) {returntemp; }if(temp.left !=null)...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node’s value equals the given value. Return the subtree rooted with that node. If such node doesn’t exist, you should return NULL. For example, Given the tree: 4 / \...
// 借助中序遍历,左根右的顺序publicTreeNodesearchBST(TreeNode root,intval){// 先判空if(root==null){returnnull;}// 如果val大于当前节点值,就往右子树里面找if(root.val<val){returnsearchBST(root.right,val);}// 如果相等,返回当前以节点为根节点的子树if(root.val==val){returnroot;}// 如果va...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. ...
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class BSTIterator: def __init__(self, root: Optional[TreeNode]): # 初始化一个空结点栈(所有结点的左子结点...
Insert into a Binary Search Tree 2. Solution Iterative /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} ...
Given the root node of a binary search tree (BST) and a value to be inserted into the tree, insert the value into the BST. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. ...
Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST.According to the definition of LCA on Wikipedia:“The lowest common ancestor is defined between two nodes p and q as the lowest node in T that has both p and q as descendants (wher...
Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? confused what"{1,#,2,3}"means?> read more on how binary tree ...