LeetCode Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the node is found, delete ...
6* public var right: TreeNode?7* public init(_ val: Int) {8* self.val = val9* self.left = nil10* self.right = nil11* }12* }13*/14classSolution {15func deleteNode(_ root: TreeNode?, _ key: Int) -> TreeNode?
Copy the data in the minimum node to the node to be deleted, and recursively call the delete function on the right subtree to delete the minimum node. Return the root of the updated binary search tree. Here is the pseudocode for deletion in a binary search tree: function deleteNode(root,...
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node has both left and right - find the minimum value in the right subtree, set that value to the currently found node, then recursively delete the minimum value in the right subtree 1/**2* Definition for a binary tree node.3* public class TreeNode {4* int val;5* TreeNode left;6*...
Search for a node to remove. If the node is found, delete the node. Note: Time complexity should be O(height of tree). Example: root = [5,3,6,2,4,null,7] key = 3 5 / \ 3 6 / \ \ 2 4 7 Given key to delete is 3. So we find the node with value 3 and delete it....
[Leetcode-Tree]Delete Node in a BST Delete Node in a BST Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages:...
LeetCode 938. Range Sum of BST 2019-12-12 08:00 − 原题链接在这里:https://leetcode.com/problems/range-sum-of-bst/ 题目: Given the root node of a binary search tree, return the sum of values of all nod... Dylan_Java_NYC 0 490 算法——dfs 判断是否为BST 2019-09-29 21...
LeetCode 702. Search in a Sorted Array of Unknown Size 2019-11-24 12:03 −原题链接在这里:https://leetcode.com/problems/search-in-a-sorted-array-of-unknown-size/ 题目: Given an integer array sorted in ascending order, write a fun... ...