1/**2* Definition for binary tree3* struct TreeNode {4* int val;5* TreeNode *left;6* TreeNode *right;7* TreeNode(int x) : val(x), left(NULL), right(NULL) {}8* };9*/10classSolution {11public:12voidrecoverTree(TreeNode *root) {13//IMPORTANT: Please reset any member data y...
In a binary search tree, (Only) two nodes are swapped. Find out these nodes and swap them. If there no node swapped, return original root of tree. Example Example1 Input: {4,5,2,1,3} Output: {4,2,5,1,3} Explanation: Given a binary search tree: 4 / 5 2 / 1 3 return 4 ...
The link ishttp://discuss.leetcode.com/questions/272/recover-binary-search-tree 1: void Solution::recoverTree(TreeNode *h) {2: TreeNode *f1=NULL, *f2=NULL;3: bool found = false;4: TreeNode *pre, *par =0; // previous AND parent5:while(h) { // Morris Traversal6:if(h->left ...
https://leetcode.com/problems/recover-binary-search-tree/ /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { stack < pair <TreeNod...
Leetcode 99. Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Example 1: Example 2: Follow up: A solution using O(n) space is pretty straight forw......
Recover Binary Search Tree -- LeetCode http://oj.leetcode.com/problems/recover-binary-search-tree/ 这道题是要求恢复一颗有两个元素调换错了的二叉查找树。一開始拿到可能会认为比較复杂,事实上观察出规律了就比較简单。主要还是利用二叉查找树的主要性质,就是中序遍历是有序的性质。那么假设当中有元素被调换...
* Definition for a binary tree node.* struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: void recoverTree(TreeNode* root) { ...
Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure.Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 这个题我看到的想法是先把所有element in order走一遍,然后存进O(n) spa...
Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? Solution1:In order dfs ...
Recover Binary Search Tree Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?