You are given therootof a binary search tree (BST) and an integerval. Find the node in the BST that the node's value equalsvaland return the subtree rooted with that node. If such a node does not exist, returnnull. Example 1: Input:root = [4,2,7,1,3], val = 2Output:[2,1...
1.递归 (一遍ac) classSolution{public:TreeNode*searchBST(TreeNode* root,intval){if(!root)returnnullptr;returnHelper(root,val); }TreeNode*Helper(TreeNode* root,intval){if(root==nullptr)returnroot;if(root->val==val)returnroot;elseif(root->val>val) root=Helper(root->left,val);elseif(root...
将所有节点值依次入队列,在入队列前先判断节点值是否等于val,等于就直接返回当前节点所在子树。 publicTreeNode searchBST(TreeNode root, intval) {if(root ==null|| root.val==val) {returnroot; } Queue<TreeNode> queue = new LinkedList<TreeNode>(); queue.offer(root);while(!queue.isEmpty()) { ...
题目链接: Binary Search Tree Iterator : leetcode.com/problems/b 二叉搜索树迭代器: leetcode-cn.com/problem LeetCode 日更第 95 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-04-25 09:24 力扣(LeetCode) Python 算法 赞同添加评论 分享喜欢收藏申请转载 ...
LeetCode 每日一题 Daily Challenge 1305 All Elements in Two Binary Search Trees 188 1 1:34 App LeetCode 每日一题 Daily Challenge 669 Trim a Binary Search Tree 189 -- 4:44 App LeetCode 每日一题 Daily Challenge 968 Binary Tree Cameras 221 -- 3:42 App LeetCode 每日一题 Daily Challenge...
基于值域的二分法与基于定义域的题型不同,它的目标是从一“特殊排序序列”中确定“第k个元素值”,而不像基于定义域的题型是从排序序列中找小于等于特定target值的第一个索引;同时,针对“特殊排序序列”,往…
Both the left and right subtrees must also be binary search trees. Example 1: Input:root = [1,null,2,2]Output:[2] Example 2: Input:root = [0]Output:[0] Constraints: The number of nodes in the tree is in the range[1, 104]. ...
Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key....
You are given the root node of a binary search tree (BST) and a value to insert into the tree. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST. Notice that there may exist multiple valid ways for the insert...
今天介绍的是LeetCode算法题中Easy级别的第163题(顺位题号是700)。给定一个二叉搜索树(BST)的和正整数val。 你需要在BST中找到节点的值等于给定val的节点。返回以该节点为根的子树。如果此节点不存在,则应返回null。例如: 鉴于树: 4 / \ 2 7 / \ 1 3 ...