You are given therootof a binary search tree (BST) and an integerval. Find the node in the BST that the node's value equalsvaland return the subtree rooted with that node. If such a node does not exist, returnn
也可以世界使用迭代的方式,借助while循环来实现,循环内部的判断逻辑和第一种解法类似,如果当前节点值大于val,就进入左子树找;如果当前节点值小于val,就进入右子树找;如果相等,直接返回以当前节点为根节点的子树。 publicTreeNode searchBST(TreeNode root, intval) {while(root !=null) {if(root.val>val) { root...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
题目地址:https://leetcode.com/problems/search-in-a-binary-search-tree/description/ 题目描述 Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node’s value equals the given value. Return the subtree rooted with...
Given the tree: 4 / \ 2 7 / \ 1 3 And the value to search: 2 1. 2. 3. 4. 5. 6. 7. 8. You should return this subtree: 2 / \ 1 3 1. 2. 3. 4. 5. In the example above, if we want to search the value 5, since there is no node with value 5, we should retur...
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题目链接: Binary Search Tree Iterator : leetcode.com/problems/b 二叉搜索树迭代器: leetcode-cn.com/problem LeetCode 日更第 95 天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满 发布于 2022-04-25 09:24 力扣(LeetCode) Python 算法 赞同添加评论 分享喜欢收藏申请转载 ...
今天的笔记包含基于树的深度优先搜索(Tree Depth-First Search)类型下的6个题目,它们在leetcode上的编号和题名分别是: 112 - Path Sum 113 - Path Sum II 437 - Path Sum III 129 - Sum Root to Leaf Numbers 543 - Diameter of Binary Tree 124 - Binary Tree Maximum Path Sum 下面将根据以上顺序分别...
今天介绍的是LeetCode算法题中Easy级别的第163题(顺位题号是700)。给定一个二叉搜索树(BST)的和正整数val。 你需要在BST中找到节点的值等于给定val的节点。返回以该节点为根的子树。如果此节点不存在,则应返回null。例如: 鉴于树: 4 / \ 2 7 / \ 1 3 ...
【Leetcode】700. Search in a Binary Search Tree 1 这里要记得添加return 注意空子树的时候要返回[],因为是serialized tree format