也可以世界使用迭代的方式,借助while循环来实现,循环内部的判断逻辑和第一种解法类似,如果当前节点值大于val,就进入左子树找;如果当前节点值小于val,就进入右子树找;如果相等,直接返回以当前节点为根节点的子树。 publicTreeNode searchBST(TreeNode root, intval) {while(root !=null) {if(root.val>val) { root...
Given the root node of a binary search tree (BST) and a value. You need to find the node in the BST that the node's value equals the given value. Return the subtree rooted with that node. If such node doesn't exist, you should return NULL. For example, Given the tree: 4 / \ ...
也可以世界使用迭代的方式,借助while循环来实现,循环内部的判断逻辑和第一种解法类似,如果当前节点值大于val,就进入左子树找;如果当前节点值小于val,就进入右子树找;如果相等,直接返回以当前节点为根节点的子树。 publicTreeNodesearchBST(TreeNode root,intval){while(root!=null){if(root.val>val){root=root.left...
题目地址:https://leetcode.com/problems/find-mode-in-binary-search-tree/#/description 题目描述 Given a binary search tree (BST) with duplicates, find all the mode(s) (the most frequently occurred element) in the given BST. Assume a BST is defined as follows: The left subtree of a node ...
/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */ type BSTIterator struct { // 结点栈(所有结点的左子结点都已经入栈过) stack []*TreeNode } func Constructor(root *TreeNode) BSTIterator { // 初始化一个空栈...
建议和leetcode 87. Scramble String 字符串拼凑 && DFS深度优先搜索 一起学习,因为我感觉递归思路相似 这道题的做法感觉和leetcode 105. Construct Binary Tree from Preorder and Inorder Traversal 中前序构造BST 和 leetcode 106. Construct Binary Tree from Inorder and Postorder Traversal 中后序构造BST 一...
总结: BST 的inorder 遍历。 ** Anyway, Good luck, Richardo! My code: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; }
Given therootof a binary search tree, atargetvalue, and an integerk, returnthekvalues in the BST that are closest to thetarget. You may return the answer inany order. You areguaranteedto have only one unique set ofkvalues in the BST that are closest to thetarget. ...
* Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} ...
LeetCode题解之 Search in a Binary Search Tree 1、题目描述 2.问题分析 利用递归遍历二叉查找树。 3、代码 1TreeNode* searchBST(TreeNode* root,intval) {2if(root ==NULL)3returnNULL;4elseif(root->val >val)5returnsearchBST(root->left, val);6elseif(root->val <val)7returnsearchBST(root->...