## LeetCode 53 最大子数列和 Maximum Subarray class Solution(): def maxSubArray(self, nums): l = len(nums) dp = [0] * l ## 初始化数组全部为0 ## 套路第三步,初始特殊值为 nums 第一个元素 dp[0] = nums[0] #res_max = dp[0] ## 最终结果也初始化为 nums 第一个元素 for i in...
classSolution{public:intmaxSubArray(vector<int>& nums){returnhelper(nums,0, nums.size() -1); }private:inthelper(vector<int>& nums,intstart,intend){if(start > end)return0;if(start == end)returnnums[start];intmid = start + (end - start) /2;intleft =helper(nums, start, mid);intr...
class Solution { public: int maxSubArray(int A[], int n) { if (A == NULL || n < 1) { return INT_MIN; } int contsum = A[0]; int maxsum = A[0]; for (int i=1; i<n; i++) { contsum = max(contsum + A[i], A[i]); maxsum = max(maxsum, contsum); } return...
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.A subarray is a contiguous part of an array. 英文版地址 leetcode.com/problems/m 中文版描述 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(...
LeetCode刷题日记 Day 28 Part 2 - Maximum Product Subarray, 视频播放量 70、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 blackwoodkane, 作者简介 ,相关视频:LeetCode刷题日记 Day 11 Part 2 - Unique Paths,LeetCode刷题日记 Day 24 Part 1
leetcode -- Maximum Product Subarray -- 重点 参考思路:http:///2014/10/leetcode-quesion-maximum-product.html 其实这里与Maximum subarray思路很像,都是dp经典。对max[i]的定义这里与Maximum subarray一致,只是要再定义一个min[i]. 这里我们其实只是讨论max[i]与max[i-1]以及min[i-1]的关系,max[i]...
Can you solve this real interview question? Maximum Product Subarray - Given an integer array nums, find a subarray that has the largest product, and return the product. The test cases are generated so that the answer will fit in a 32-bit integer. E
leetcode 53. Maximum Subarray Given an integer arraynums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Example: Input:[-2,1,-3,4,-1,2,1,-5,4], Output:6 Explanation:[4,-1,2,1]has the largest sum =6....
Can you solve this real interview question? Number of Subarrays with Bounded Maximum - Given an integer array nums and two integers left and right, return the number of contiguous non-empty subarrays such that the value of the maximum array element in th
the contiguous subarray [4,-1,2,1] has the largest sum = 6.中文:主要是给定一个数组,求解数组的子数组中,数组元素和最大的那一个子数组,返回的是最大子数组的和。2. 求解解法一最简单也是最容易想到的思路就是三层循环,对(i,j),i<=j的情况进行遍历,这种情况下的算法复杂度为O($n^3$)。代码如...