Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4]Output: 6Explanation: [2,3] has the largest product 6.Example 2: Input: [-2,0,-1]Output: 0Explanation: The result...
Product of Array Except Self Maximum Product of Three Numbers Subarray Product Less Than K 参考资料: https://leetcode.com/problems/maximum-product-subarray/ https://leetcode.com/problems/maximum-product-subarray/discuss/48302/2-passes-scan-beats-99 https://leetcode.com/problems/maximum-product-su...
不是求最大乘积嘛,因为如果当前数是负的,并且当前最小值也是负的,那么乘积可能就是下一个最大值。 LeetCode官方题解递推公式: Let us denote that: f(k) = Largest product subarray, from index 0 up to k. Similarly, g(k) = Smallest product subarray, from index 0 up to k. Then, f(k) =...
所以LeetCode第53题Maximum Subarray,只需要定义一个变量,用来记录和;本题要定义两个变量:positive和negative,分别记录当前乘积最大值和最小值。 publicintmaxProduct(int[]nums){int max=nums[0];int positive=nums[0];int negative=nums[0];for(int i=1;i<nums.length;i++){positive*=nums[i];negative*...
Can you solve this real interview question? Maximum Product Subarray - Given an integer array nums, find a subarray that has the largest product, and return the product. The test cases are generated so that the answer will fit in a 32-bit integer. E
https://leetcode.com/problems/maximum-product-subarray/ 题目: Find the contiguous subarray within an array (containing at least one number) which has the largest product. [2,3,-2,4], the contiguous subarray[2,3]has the largest product =6. ...
LeetCode: 152. Maximum Product Subarray 题目描述 Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1: Input: [2,3,-2,4] Output: 6 Explanation: [2,3] has the largest product 6. ...
LeetCode刷题日记 Day 28 Part 2 - Maximum Product Subarray, 视频播放量 70、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 blackwoodkane, 作者简介 ,相关视频:LeetCode刷题日记 Day 11 Part 2 - Unique Paths,LeetCode刷题日记 Day 24 Part 1
## LeetCode 53 最大子数列和 Maximum Subarray class Solution(): def maxSubArray(self, nums): l = len(nums) dp = [0] * l ## 初始化数组全部为0 ## 套路第三步,初始特殊值为 nums 第一个元素 dp[0] = nums[0] #res_max = dp[0] ## 最终结果也初始化为 nums 第一个元素 for i in...
Explanation: The result cannot be 2, because [-2,-1] is not a subarray.</pre> 思路: 一开始的暴力解法,找出所有的子数组,算出乘积,然后找出比较大的一个。但是复杂度是n2;换思路,dp来做,要用两个dp数组。其中f[i]表示[0,i]范围内并且包含nums[i]的最大子数组乘积。g[i]标识[0,i]范围内并且...