不是求最大乘积嘛,因为如果当前数是负的,并且当前最小值也是负的,那么乘积可能就是下一个最大值。 LeetCode官方题解递推公式: Let us denote that: f(k) = Largest product subarray, from index 0 up to k. Similarly, g(k) = Smallest product subarray, from index 0 up to k. Then, f(k) =...
LeetCode 152. Maximum Product Subarray 程序员木子 香港浸会大学 数据分析与人工智能硕士在读 来自专栏 · LeetCode 1 人赞同了该文章 Description Given an integer array nums, find the contiguous subarray within an array (containing at least one number) which has the largest product. Example 1...
Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array [2,3,-2,4], the contiguous subarray [2,3] has the largest product =6. 2.翻译 1 2 3 4 找最大的数组中的子数组乘积 例如,给予的数组是[2,3,-2,...
the contiguous subarray[2,3]has the largest product =6 思路:从左至右遍历数组,记录下以当前所遍历到的元素结尾的子数组积的最大值和最小值(由于数组里面可能存在负数),同一时候记录下得到的全部最大值中最大的。循环结束时。得到的全部最大值中最大的即为所求。 代码: int Solution::maxProduct(int A[...
https://oj.leetcode.com/problems/maximum-product-subarray/ 题目分析:求一个数组,连续子数组的最大乘积。 解题思路:最简单的思路就是3重循环。求解productArray[i][j]的值(productArray[i][j]为A[i]到A[j]的乘积),然后记录当中最大值,算法时间复杂度O(n3)。必定TLE。
the contiguous subarray [2,3] has the largest product = 6. Array Dynamic Programming SOLUTION 1 使用DP来做: 因为有正负值好几种情况。所以我们计算当前节点最大值,最小值时,应该考虑前一位置的最大值,最大值几种情况。(例如:如果当前为-2, 前一个位置最小值为-6,最大值为8,那么当前最大值应该是...
the contiguous subarray[2,3]has the largest product =6. 简单来说就是在一个 int 数组中找一段连续的子数组,使其乘积最大,数组中包含正数、负数和0。不考虑乘积太大超出范围。 解法一: 动态规划的方法,今天在微信“待字闺中”中看到的,借来分享。遍历一遍,优于解法二,复杂度O(n). ...
【LeetCode】152. Maximum Product Subarray Maximum Product Subarray Find the contiguous subarray within an array (containing at least one number) which has the largest product. For example, given the array[2,3,-2,4], the contiguous subarray[2,3]has the largest product =6....
the contiguous subarray[2,3]has the largest product =6. 题解: 先暴力解,遍历所有组合,更新最大值。很显然得超时。 Solution 1 (TLE) classSolution {public:intmaxProduct(vector<int>&nums) {intn = nums.size(), mproduct = nums[0];for(inti =0; i < n; ++i) {inttmp =nums[i]; ...
Output:6Explanation: [2,3] has the largest product 6. Example 2: Input: [-2,0,-1] Output: 0 Explanation: The result cannot be 2, because [-2,-1] is not a subarray. 这个求最大子数组乘积问题是由最大子数组之和Maximum Subarray演变而来,但是却比求最大子数组之和要复杂,因为在求和的时...