一、最大连续子序列和 https://leetcode.com/problems/maximum-subarray/description/ https://www.geeksforgeeks.org/largest-sum-contiguous-subarray/ The core ideas are the same: currentMax = max(nums[i], some_operation(currentMax, nums[i])). For each element, we have 2 options: put it insi...
classSolution {public:intmaxSubArray(vector<int>&nums) {//明显的动态规划,因为是连续的,所以这个子序列:1.取前面和后面的元素则和变小,//比如,如果4,左边的dp(取该元素)是依次[-2,1,-2,4,3,5,6,1,5][]if(nums.empty())return0; vector<int>vec; vec.push_back(nums[0]);for(inti=1;i!
这个问题是这样的(https://leetcode.com/problems/maximum-subarray/): Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. 就是给一组整数,找到一组连续的子序列,让子序列的和最大,并且返回最大和。 比如说: 输入...
0152-Maximum-Product-Subarray 0153-Find-Minimum-in-Rotated-Sorted-Array 0155-Min-Stack 0159-Longest-Substring-with-At-Most-Two-Distinct-Characters 0160-Intersection-of-Two-Linked-Lists 0161-One-Edit-Distance 0167-Two-Sum-II-Input-array-is-sorted 0169-Majority-Element 01...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
(Medium) Maximu Product Subarray classSolution {publicintmaxProduct(int[] nums) {if(nums ==null|| nums.length ==0){return0; }intmax = nums[0];intmin = nums[0];intres = nums[0];for(inti = 1; i<nums.length; i++){if(nums[i]<0){inttmp =min;...
classSolution {public:intmaxPoints(vector<Point>&points) { unordered_map<float,int>m;if(points.size() <1)return0;intret_max =INT_MIN;for(inti =0; i < points.size(); i++){inttmp_max =0; m.clear();intsame =0;for(intj = i+1; j < points.size(); j++){if(points[i].x ...
Givennpoints on a 2D plane, find the maximum number of points that lie on the same straight line. Example 1: Input: [[1,1],[2,2],[3,3]] Output: 3 Explanation: ^ | | o | o | o +---> 0 1 2 3 4 Example 2: Input...