package SlidingWindow; import java.util.Scanner; public class maximumSumSubarray { public static void main(String args[]) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); int arr[]=new int[n]; for(int i=
classSolution {publicintmaxSubArray(int[] nums) {intmaxSum = Integer.MIN_VALUE;//注意有负数的时候,不能初始化为0intcurrentSum =Integer.MIN_VALUE;for(inti = 0; i < nums.length; i++){if(currentSum < 0) currentSum =nums[i];elsecurrentSum +=nums[i];if(currentSum > maxSum) maxSum ...
糖醋里脊 Maximum Subarray (JAVA) Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array[−2,1,−3,4,−1,2,1,−5,4], the contiguous subarray[4,−1,2,1]has the largest sum =6. 1publicstaticintma...
遍历数组: sum加上当前值后, 1)先判断max是否需要更新 2)再判断sum是否小于0, 小于0的话sum更新为0, 大于0的话sum不变,继续累积 */ class Solution { public int maxSubArray(int[] nums) { int sum = 0, max = Integer.MIN_VALUE; for(int i=0; i<nums.length; i++){ //execute sum += n...
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.A subarray is a contiguous part of an array. 英文版地址 leetcode.com/problems/m 中文版描述 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(...
53. Maximum Subarray*(最大子序和) 53. Maximum Subarray* (最大子序和) https://leetcode.com/problems/maximum-subarray/ 题目描述 Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and returnits ...
Implement Maximum Subarray Sum Algorithm Original Task Write a function that takes an array of integers and returns the maximum sum of a contiguous subarray, handling both positive and negative num...
LeetCode - The World's Leading Online Programming Learning Platformleetcode.com/problems/maximum-gcd-sum-of-a-subarray/description/ 简单介绍一下题目大意,更详细的描述可以见链接中的原题描述及样例数据: 给定一个长度为n的正整数数组nums。对于nums的任意一个子数组(连续、非空的一段),定义s为子数组...
Now to combine two arrays, the maximum subarray sum of the combined array would bemax(p(1)2,p(2)2,p(1)2+p(1)3+p(2)1+p(2)2)max(p2(1),p2(2),p2(1)+p3(1)+p1(2)+p2(2)). The remaining left and right side parts can be maintained easily. ...
leetcode实际执行结果:beats Java submit 96.89% - 9ms 下面上代码: publicintmaxSubArray(int[]nums){intmax=nums[0];intdp_n=nums[0];inttmp;for(inti=1;i<nums.length;i++){dp_n=nums[i]+(dp_n>0?dp_n:0);max=dp_n>max?dp_n:max;}returnmax;} ...