java代码如下: 1publicclassSolution {2publicintmaxSubArray(int[] A) {3intsum=A[0],tmp=A[0];4for(inti=1;i<A.length;i++){5if(tmp>0){6tmp+=A[i];7}8else{9tmp=A[i];10}11if(tmp>sum){12sum=tmp;13}14}15returnsum;16}17} pyt
第一次做, 最重要的就是理清处理顺序, 遍历数组时, 将当前值arr[i]加入到sum后再对sum进一步处理; 也就是说并不是先处理sum再处理arr[i], 而是先处理arr[i]再处理sum; 其实还是先处理sum比较好, 看下面的题解 /* 连续子数组的最大和 遍历数组: sum加上当前值后, 1)先判断max是否需要更新 2)再判断...
那么对于增大k+1这个元素从而去组成最大子序列是没有贡献的,所以能够把sum 置0。 代码实现 算法实现类 publicclassSolution{publicintmaxSubArray(int[] nums){// 參数校验if(nums ==null|| nums.length <1) {thrownewIllegalArgumentException(); }intmax = Integer.MIN_VALUE;intcurSum =0;for(inti : nu...
Breadcrumbs AAPS /SlidingWindow / maximumSumSubarray.javaTop File metadata and controls Code Blame 43 lines (35 loc) · 824 Bytes Raw package SlidingWindow; import java.util.Scanner; public class maximumSumSubarray { public static void main(String args[]) { Scanner sc=new Scanner(System.in)...
[Leetcode] Maximum Subarray 子序列最大和 Maximum Subarray 最新更新请见:https://yanjia.me/zh/2019/02/... Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [−2,1,−3,4,−1,2,1,−5,4], the...
Java实现代码如下: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 publicclassMaximumSubarray{publicintmaxSubArray(int[]nums){int maxEndHere=0;int maxSoFar=0;for(int i=0;i<nums.length;i++){maxEndHere+=nums[i];if(maxEndHere<0){maxEndHere=0;}if(maxSoFar<maxEndHere){maxSoFar=maxEnd...
Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.A subarray is a contiguous part of an array. 英文版地址 leetcode.com/problems/m 中文版描述 给你一个整数数组 nums ,请你找出一个具有最大和的连续子数组(...
Day2-2 leetcode 53. Maximum Subarray Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum. Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer ...
「哈希表法:Java」 public class Solution { /** type nums: int type k: int rtype: int */ public int maxSubArrayLen(int[] nums, int k) { int sum = 0, max = 0; HashMap<Integer, Integer> map = new HashMap<Integer, Integer>(); for (int i = 0; i < nums.length; i++) {...
Explanation: [4,-1,2,1] has the largest sum = 6. 1. 2. 3. Follow up: If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle. class Solution { public int maxSubArray(int[] nums) { ...