I have time series data that corresponds with eachother. I have two matrices of the same length, that have force and length of a muscle. I want to find the index of the max value of force and use that index to
___= max(___,"ComparisonMethod",method) Description M= max(A)returns the maximum elements of an array. IfAis a vector, thenmax(A)returns the maximum ofA. IfAis a matrix, thenmax(A)is a row vector containing the maximum value of each column ofA. ...
i have a matrix size 378x5, how do i find the index column of the maximum value of each row? Thanks 댓글 수: 1 Rik2019년 5월 30일 (I'm on mobile so I can't check) The second output of max can do this. You may need to use a loop. ...
fprintf('value of a: %d \n', a); end 1. 2. 3. 输出结果为: value of a: 10 value of a: 11 value of a: 12 value of a: 13 value of a: 14 value of a: 15 value of a: 16 value of a: 17 value of a: 18 value of a: 19 value of a: 20 1. 2. 3. 4. 5. 6. ...
[value, location] = max(A, [],'all','linear') value = 10 location = 11 Create an all zero array the same size as A. B = zeros(size(A)); Set the element in B corresponding to the location of the maximum value in A to that maximum value. ...
Write MatLab commands to find the index of the max value in the bold area of AThis would ...
How to calculate a max value in a array without the built in functions.is a built-in function) prohibit the use of built-in functions. This information is in the title of the original question, not the body. [Yes, technically the question doesn't state this was a...
% options structure in PROBLEM.options, and solver name 'fmincon' in % PROBLEM.solver. Use this syntax to solve at the command line a problem % exported from OPTIMTOOL. The structure PROBLEM must have all the fields. % % [X,FVAL] = FMINCON(FUN,X0,...) returns the value of the obje...
nTime = size(ErrKarray,3); % number of time steps in each simulation ErrKPos = zeros(1, nTime); % position error of unconstrained Kalman filter ErrKVel = ErrKPos; % velocity error of unconstrained Kalman filter ErrKCPos = ErrKPos; % position error of constrained Kalman filter ErrK...
maksimum=max(abs(U(i:end,i))); Index in position 2 exceeds array bounds. Index must not exceed 5 "Index in position 2" means the 2nd index value in u(i:end, i) which is the last i. That i is causing a problem. "Index in position 2 exceeds array bounds" mea...