LeetCode 9 的题目是 “Palindrome Number”(回文数)。题目要求如下: 题目描述: 给定一个整数 x,判断它是否是一个回文数。回文数是指正着读和倒着读都一样的整数。 示例: 输入: 121 输出: true 输入: -121 输出: false 解释: 倒着读是 121-,所以不是回文数。可见,所有负数都不是回文数字。 输入: 10 输出
Determine whether an integer is a palindrome. Do this without extra space. 思路:若使用【Leetcode】Reverse Integer的方法。推断反转后的整数是否与原整数同样,则可能出现溢出情况;又由于题目要求不适用额外空间,能够之间对照整数第一个与最后一个数的值。再依次类推。 class Solution { public: bool isPalindro...
Leetcode:9. Palindrome Number 题目: Leetcode:9. Palindrome Number 描述: 内容:Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction ...
1. 2. 3. Example 3: Input: 10 Output: false Explanation: Reads 01 from right to left. Therefore it is not a palindrome. 1. 2. 3. Follow up: Coud you solve it without converting the integer to a string? class Solution(object): def isPalindrome(self, x): """ :type x: int :r...
Determine whether an integer is a palindrome. Do this without extra space. 2、代码实现 代码实现1 public static boolean isPalindrome(int x) { if (x < 0) { return false; } String s = String.valueOf(x); char[] chars = s.toCharArray(); ...
public boolean isPalindrome(int x) { if(x < 0 || (x % 10 == 0 && x != 0)) return false; int revertedNumber = 0; while(x > revertedNumber) { revertedNumber = revertedNumber * 10 + x % 10; x /= 10; } return x == revertedNumber || x == revertedNumber/10; } 时间复...
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Additive Number 【题目】Additive number is a string whose digits can form additive sequence. A valid additive sequence should contain at least three numbers. Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two. For example: "112358...
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For the purpose of this problem, we define empty string as valid palindrome. 【解答】注意大小写,注意数字和字母都要算有效字符。 代码语言:javascript 代码运行次数:0 运行 AI代码解释 public class Solution { public boolean isPalindrome(String s) { int left = 0; int right = s.length()-1; whil...