1classSolution(object):2defisPalindrome(self, x):3"""4:type x: int5:rtype: bool6"""7x2 = str(x)8ifx2 == x2[::-1]:9returnTrue10else:11returnFalse 一个比较精简的代码 运行时间打败了97%的代码 但是很占内存
Given a strings, partitionssuch that every substring of the partition is a palindrome. Return the minimum cuts needed for a palindrome partitioning ofs. For example, givens="aab", Return1since the palindrome partitioning["aa","b"]could be produced using 1 cut. » Solve this problem [Thought...
Solution 代码语言:javascript 代码运行次数:0 运行 AI代码解释 class Solution { public: string shortestPalindrome(string s) { if(s.size() < 2) { return s; } int max_length = 1; for(int i = 0; i <= s.size() / 2; ) { int left = i; int right = i; while(s[i] == s[righ...
代码如下: ## LeetCode 9, 回文数,简单写法1:classSolution:defisPalindrome(self,x:int)->bool:y=str(x)## 转换为字符串z=y[::-1]## 对字符串进行反转returny==z 解法2. 简单写法的精简版 转换和反转的操作,都可以放入return语句。 ## LeetCode 9, 回文数,简单写法1的精简版classSolution:defisPa...
class Solution { public boolean isPalindrome(int x) { if(x<0) { return false; } if(x==0) { return true; } StringBuilder in = new StringBuilder(); int a = x; while(a!=0) { in.append(a%10); a/=10; } String o = String.valueOf(x); ...
class Solution { public: vector<vector<string>> partition(string s) { vector<vector<string>> res; helper(s, res, {}); return res; } void helper(string s, vector<vector<string>>& res, vector<string> path) { if (s.size() == 0) { ...
Leetcode-Easy 234. Palindrome Linked List 描述: 判断一个单链表是否左右对称 代码语言: 代码运行次数: # Definitionforsingly-linked list.#classListNode:# def__init__(self,x):# self.val=x # self.next=NoneclassSolution(object):defisPalindrome(self,head):""":type head:ListNode:rtype:bool"""...
class Solution: def romanToInt(self,rnum): rnum = input("input:") dic = {"I":1,"V":5,"X":10,"L":50,"C":100,"D":500,"M":1000} rnum = list(rnum) s =0 if len(rnum) <1 or len(rnum)> 15: return 0 for i in range(len(rnum)-1): if dic[rnum[i]] < dic...
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输入:s = "leetcode" 输出:5 解释:插入 5 个字符后字符串变为 "leetcodocteel" 。 提示: 1 <= s.length <= 500 s 中所有字符都是小写字母。 思路: 动态规划 - 最长子序列 将字符串 s 反序得到 s' 设s 与 s‘ 的最长子序列为 m