Java 实现 classSolution{publicbooleanisPalindrome(intx){StringreversedStr=(newStringBuilder(x +"")).reverse().toString();return(x +"").equals(reversedStr); } } Python 实现 classSolution:defisPalindrome(self, x):""" :type x: int :rtype: bool """returnstr(x) ==str(x)[::-1] 复杂...
1classSolution(object):2defisPalindrome(self, x):3"""4:type x: int5:rtype: bool6"""7x2 = str(x)8ifx2 == x2[::-1]:9returnTrue10else:11returnFalse 一个比较精简的代码 运行时间打败了97%的代码 但是很占内存
Coud you solve it without converting the integer to a string? 这题正好用到上一题的方法 【LeetCode算法】Reverse Integer 代码: classSolution {publicbooleanisPalindrome(intx) {if(x<0){returnfalse; }else{inty = 0;intz =x;while(x/10!=0){ y*=10; y+=x%10; x/=10; } y=y*10+x;if...
代码如下: ## LeetCode 9, 回文数,简单写法1:classSolution:defisPalindrome(self,x:int)->bool:y=str(x)## 转换为字符串z=y[::-1]## 对字符串进行反转returny==z 解法2. 简单写法的精简版 转换和反转的操作,都可以放入return语句。 ## LeetCode 9, 回文数,简单写法1的精简版classSolution:defisPa...
Leetcode 3——Palindrome Number(回文数) Problem: Determine whether an integer is a palindrome. Do this without extra space. 简单的回文数,大一肯定有要求写过,不过从基础开始尝试吧。 Solution: publicclassSolution {publicbooleanisPalindrome(intx) {intn=1;intcopyx=x;if(x<0)returnfalse;if(x<10)...
LeetCode题解(9)--Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. 思想: 先计算出这个整数的逆序数,然后比较它和原来的数每位是否都相同即可。另外要注意负数没有回文数,还应该考虑overflow一定不是回文数。
classSolution {private://leetcode9longlongreverseInt(intx) {longlongresult =0;while(x) { result= result *10+ x%10; x/=10; }returnresult; }public://no extra spaceboolisPalindrome(intx) {if(x <0)returnfalse;if(x <10)returntrue;if(reverseInt(x) ==x)returntrue;elsereturnfalse; ...
code 1/*2Time Complexity: O(n), loop each digit of input number3Space Complexity: O(1), allocate a variable temp4*/5classSolution {6publicbooleanisPalindrome(intx) {7//handle input is negative like -121 or end with 08if(x < 0 || (x != 0 && x % 10 == 0))returnfalse;910...
【Leetcode】Palindrome Number Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space....
Leetcode #9 Easy <Palindrome Number> 题目如图,下面是我的解决方法: 1classSolution {2publicbooleanisPalindrome(intx) {3if(x < 0) //由题意可知,小于0的数不可能为回数, 因此直接返回false 4returnfalse;5else{67String len = x + "";8int[] arr =newint[len.length()]; //创建数组arr, ...