Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input:121Output:true Example 2: Input:-121Output:falseExplanation:From left to righ
Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input:121Output:true Example 2: Input:-121Output:falseExplanation:Fromlefttoright, it reads -121.Fromrighttoleft, it becomes121-. Therefore itisnota palindrome. Examp...
1、题目 Determine whether an integer is a palindrome. Do this without extra space. 2、代码实现 代码实现1 public static boolean isPalindrome(int x) { if (x < 0) { return false; } String s = String.valueOf(x); char[] chars = s.toCharArray(); int length = chars.length; for (int ...
Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121 Output: true 1. 2. Example 2: Input: -121 Output: false Explanation: From left to right, it reads -121. From right to left, it becomes 121-. ...
这是LeetCode 刷题系列的第 5 道题。 题号:9 题名:Palindrome Number 问题描述 Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example Example 1: Input: 121 Output: true Example 2: Input: -121 Output: false Explanation: ...
除法之后保留整数结果 - Floor division - division that results into whole number adjusted to the left in the number linereturnx==y## 改进版## LeetCode 9, 回文数,不转换为字符串的写法1:## 这个解法的详细解读,可参考下一个解法classSolution:defisPalindrome(self,x:int)->bool:ifx<0:returnFalse...
funcisPalindrome(_ x:Int)->Bool{var str=String()letchas=String(x).reversed()forcinchas{str.append(c)}ifString(x)==str{returntrue}returnfalse} 【思路2】 1、从x的各位到最高位 依次遍历得到一个新数值,判断两个数值是否相等 2、时间复杂度O(log10ºn),(以十为底n的对数)因为每次都会除以10...
LeetCode NO. 9 Palindrome Number LeetCode 第9题 回文数 DIFFICULTY(难度) EASY 容易 DESCRIPTION(题面) Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. 判断一个整数是否是回文数,回文数就是正读反读都相同的数字 ...
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[leetcode]Palindrome number 回文数 题目描述: 首先负数一定不是回文数,0是回文数,10的倍数一定不是回文数10000 方法1 ,跟前面的求数的逆序一样,求出逆序数,与原数比较即可,需要借助temp: classSolution{ public: boolisPalindrome(intx){ if(x <0)...