Can you solve this real interview question? Palindrome Number - Given an integer x, return true if x is a palindrome, and false otherwise. Example 1: Input: x = 121 Output: true Explanation: 121 reads as 121 from left to right and from right to lef
【LeetCode题解】9_回文数(Palindrome-Number) 9_回文数(Palindrome-Number) 目录 9_回文数(Palindrome-Number) 描述 解法一:转化为字符串的比较 思路 Java 实现 Python 实现 复杂度分析 解法二:反转数字的后半部分 ★ 思路 Java 实现 Python 实现 复杂度分析 描述 判断一个整数是否是回文数。回文数是指正序(...
public boolean isPalindrome(int x) { if(x < 0 || (x % 10 == 0 && x != 0)) return false; int revertedNumber = 0; while(x > revertedNumber) { revertedNumber = revertedNumber * 10 + x % 10; x /= 10; } return x == revertedNumber || x == revertedNumber/10; } 时间复...
}();classSolution{public:boolisPalindrome(intx){if(x <0|| (x %10==0&& x !=0)) {returnfalse; }intreverseNumber =0;while(x > reverseNumber) { reverseNumber = reverseNumber *10+ x %10; x /=10; }returnx == reverseNumber || x == reverseNumber /10; } }; 这个方法是在我之上...
除法之后保留整数结果 - Floor division - division that results into whole number adjusted to the left in the number linereturnx==y## 改进版## LeetCode 9, 回文数,不转换为字符串的写法1:## 这个解法的详细解读,可参考下一个解法classSolution:defisPalindrome(self,x:int)->bool:ifx<0:returnFalse...
https://leetcode.com/problems/palindrome-number/ 题目: Determine whether an integer is a palindrome. Do this without extra space. Some hints: Could negative integers be palindromes? (ie, -1) If you are thinking of converting the integer to string, note the restriction of using extra space....
https://leetcode.com/problems/palindrome-number/ understanding: 题目原意是要我们用数学的办法去coding,而不是转化成string。但转化成string也可以通过。 my code: class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool ...
LeetCode力扣 907. 子数组的最小值之和 Sum of Subarray Minimums 110 -- 9:07 App LeetCode力扣 509. 斐波那契数 Fibonacci Number 132 -- 12:17 App LeetCode力扣 697. 数组的度 Degree of an Array 23 -- 7:21 App LeetCode力扣 154. 寻找旋转排序数组中的最小值 II Find Minimum in Rotated...
判断一个整数是否是回文数。回文数是指正序(从左向右)和倒序(从右向左)读都是一样的整数。 【示例1】 输入: 121 输出: true 【示例1】 输入: -121 输出: false 解释: 从左向右读, 为 -121 。 从右向左读, 为 121- 。因此它不是一个回文数。
LeetCode NO. 9 Palindrome Number LeetCode 第9题 回文数 DIFFICULTY(难度) EASY 容易 DESCRIPTION(题面) Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. 判断一个整数是否是回文数,回文数就是正读反读都相同的数字 ...