leetcode 第九题 Palindrome Number(java) Palindrome Number time=434ms 负数不是回文数 public class Solution { public boolean isPalindrome(int x) { int palindrome=0; int revers=x; if(revers<0) return false; else{ while(revers>0){ int m=revers%10; palindrome=m+palindrome*10; revers=revers/...
Java实现: 1publicclassSolution {2publicbooleanisPalindrome(intx) {3intm=x;4inty=0;5if(x<0)returnfalse;6while(m>0){7y=y*10+m%10;8m/=10;9}10returnx==y;11}12}
LeetCode-Java-9. Palindrome Number 题目 Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. 确定整数是不是回文数,当整数向前和向后读相同的时候,就是回文数 Example 1: Input: 121 Output: true Example 2: Input: -121 Output: fa...
AC代码: publicclassSolution{privateinti;privateintlabelnum;privatelongfinalnum;privateintfinalnnum;privateintcheckresult;privateintlabel;privateinty;privatebooleanblabel;publicbooleanisPalindrome(intx){y=reverse(x);//将原整数进行转置if(y==0){if(x==y)blabel=true;//转制前后都是0elseblabel=false;/...
* @链接:https://leetcode-cn.com/problems/palindrome-number/solution/ji-bai-liao-99de-javayong-hu-dai-ma-you-ya-by-reed/ */publicbooleanisPalindrome(int x){if(x<0){returnfalse;}int help=1;int tmp=x;while(tmp>=10){help*=10;tmp/=10;}while(x!=0){if(x%10!=x/help){returnfals...
class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool """ if x < 0: return False temp = x y = 0 while temp: y = y*10 + temp%10 temp /= 10 return x == y 总结 由于不允许占用额外空间,所以不能将其分为字符串来做。 本文参与 腾讯云自媒体同步曝...
有意思的是这种方法对应的 C++ 写法会 TLE,跟上面正好相反,那么我们是否能得出 Java 的 substring 操作略慢,而 C++ 的 reverse 略慢呢,博主也仅仅是猜测而已。 public class Solution { public String shortestPalindrome(String s) { int i = 0, end = s.length() - 1, j = end; char arr = s....
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434Number of Segments in a StringPythonJava1. trim &split 2. Find segment in place 437Path Sum IIIPythonJava1. Recursively travese the whole tree, O(n^2) 2. Cache sum in Hash based on solution 1. Note that if sum(A->B)=target, then sum(root->a)-sum(root-b)=target. ...
class Solution { public String longestPalindrome(String s) { if (s == null || s.length() < 2) return s; //return as result String longest = s.substring(0, 1); for (int i = 0; i < s.length()-1; i++) { //get 'ABA' type palindrome ...