class Solution(object): def isPalindrome(self, x): """ :type x: int :rtype: bool """ if x < 0: return False temp = x y = 0 while temp: y = y*10 + temp%10 temp /= 10 return x == y 总结 由于不允许占用额外空间,所以不能将其分为字符串来做。 本文参与 腾讯云自媒体同步曝...
Java 实现 classSolution{publicbooleanisPalindrome(intx){StringreversedStr=(newStringBuilder(x +"")).reverse().toString();return(x +"").equals(reversedStr); } } Python 实现 classSolution:defisPalindrome(self, x):""" :type x: int :rtype: bool """returnstr(x) ==str(x)[::-1] 复杂...
1classSolution(object):2defisPalindrome(self, x):3"""4:type x: int5:rtype: bool6"""7x2 = str(x)8ifx2 == x2[::-1]:9returnTrue10else:11returnFalse 一个比较精简的代码 运行时间打败了97%的代码 但是很占内存
Example 3: Input: 10Output:falseExplanation: Reads01 from right to left. Therefore it is not a palindrome. Follow up: Coud you solve it without converting the integer to a string? 这题正好用到上一题的方法 【LeetCode算法】Reverse Integer 代码: classSolution {publicbooleanisPalindrome(intx) {...
classSolution{public:boolisPalindrome(intx){ vector<int>res;if(x<0)returnfalse;if(x==0)returntrue;while(x) { res.push_back(x%10); x/=10; }inti =0,j = res.size()-1;while(i<=j) {if(res[i]!=res[j])returnfalse; ++i; ...
代码 classSolution{public:boolisPalindrome(intx){stringsx = to_string(x);intlen = sx.size();inti =0;while(i <= len/2) {if(sx[i] == sx[len-1-i]) { i++;continue; }elsereturnfalse; }returntrue; } };
classSolution{publicbooleanisPalindrome(intx){//将后一半反转,与前一半比较//重点:如何知道我们已经反转到了一半,剩下的数字小于已经反转完成的数字if(x<0|| (x%10==0&& x!=0))//负数都不可能是回文数,最后一位是0的除0之外都不可能是回文数returnfalse;intreverse=0;while(x>reverse){ ...
}();classSolution{public:boolisPalindrome(intx){if(x <0|| (x %10==0&& x !=0)) {returnfalse; }intreverseNumber =0;while(x > reverseNumber) { reverseNumber = reverseNumber *10+ x %10; x /=10; }returnx == reverseNumber || x == reverseNumber /10; ...
LeetCode 9. Palindrome Number https://leetcode.com/problems/palindrome-number/ 试了几种办法,这个应该是比较快的。 classSolution {public:boolisPalindrome(intx) {if(x<0)returnfalse;intfuck=log10(x);intnum=0,mid=(fuck)>>1;for(inti=0;i<=mid;i++)...
除法之后保留整数结果 - Floor division - division that results into whole number adjusted to the left in the number linereturnx==y## 改进版## LeetCode 9, 回文数,不转换为字符串的写法1:## 这个解法的详细解读,可参考下一个解法classSolution:defisPalindrome(self,x:int)->bool:ifx<0:returnFalse...