$$ t= \sqrt{x-3} $$ $$ x=t^{2}+3 $$ $$ \int \frac{t^{2}+3}{t}d(t^{2}+3) \\ = \int \frac{(t^{2}+3)\cdot 2tdt}{t} \\ = \int 2t^{2}dt+ \int 6dt \\ = \frac{2}{3}t^{3}+6t+c $$ ∴ $$ 代入x. \\ = \frac{2}{3}(x-3)^...
解析 \$\int \sqrt { x } ( x - 3 ) \mathrm { d } x = \int \left( x ^ { 3 / 2 } - 3 x ^ { 1 / 2 } \right) \mathrm { d } x = \frac { 2 } { 5 } x ^ { 5 / 2 } - 2 x ^ { 3 / 2 } + C\$ ...
Answer to: Integrate the following \int \frac{\sqrt{x}-x^{\frac{3}{x}}+{1}}{x}dx \int_{2}^{3}\frac{x}{1-x^{2}}dx \int \sin x\cos x dx By signing...
Solve: frac(2)(z+4)= frac(1)(z-6) Solve: y=ln(\sqrt { x+6}) Solve ((2x + 5) / 2) - (3x / (x - 2)) = x Solve: (2x)^4 (3x^3)^2 Solve for x: x^3 = 1 - i. Solve 2x = 5 Solve 3x - 6 = 0 Solve for x: x^2e^x-5x e^x = 0 Solve for x if 4...
Answer to: Evaluate the integral. \int \frac{x}{\sqrt{3x-1}}\,dx By signing up, you'll get thousands of step-by-step solutions to your homework...
解析 【解析】 $$ x + \frac { 6 } { 5 } x ^ { \frac { 5 } { 6 } } + \frac { 3 } { 2 } x ^ { \frac { 2 } { 3 } } + 2 \sqrt { x } + 3 \sqrt [ 3 ] { x } + 6 \sqrt [ 6 ] { x } + 6 \ln | \sqrt [ 6 ] { x } - 1 | + c $$...
百度试题 结果1 题目(10)$$ \int \frac { \sqrt { x } } { \sqrt { x } - \sqrt [ 3 ] { x } } d x $$ 相关知识点: 试题来源: 解析 $$ 2 \times 7 $$ + 2 反馈 收藏
{eq}\displaystyle \int \frac{3x}{3 \sqrt{3 - 7x^2}}dx {/eq} Indefinite Integral: The integral in which the value of the upper limit and the lower limit is not given is known as the indefinite integral. The value of this type of integral is not fixed that's why we add ...
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Answer to: Evaluate the integral: \int \frac{1}{\sqrt{x} - \sqrt[3]{x}} dx By signing up, you'll get thousands of step-by-step solutions to your...