$$ t= \sqrt{x-3} $$ $$ x=t^{2}+3 $$ $$ \int \frac{t^{2}+3}{t}d(t^{2}+3) \\ = \int \frac{(t^{2}+3)\cdot 2tdt}{t} \\ = \int 2t^{2}dt+ \int 6dt \\ = \frac{2}{3}t^{3}+6t+c $$ ∴ $$ 代入x. \\ = \frac{2}{3}(x-3)^...
解析 \$\int \sqrt { x } ( x - 3 ) \mathrm { d } x = \int \left( x ^ { 3 / 2 } - 3 x ^ { 1 / 2 } \right) \mathrm { d } x = \frac { 2 } { 5 } x ^ { 5 / 2 } - 2 x ^ { 3 / 2 } + C\$ ...
{eq}\int \frac{\sqrt{x}-x^{\frac{3}{2}}+{1}}{x}dx {/eq} {eq}\int_{2}^{3}\frac{x}{1-x^{2}}dx {/eq} {eq}\int \sin x\cos x dx {/eq} Indefinite Integral: Given any function, {eq}f(x) {/eq}, an anti-deriv...
Compute the double integral \int_0^2 \int_{x^2}^4 x \sqrt{3 + \frac{x^2}{y \,dy \,dx A.) Find the indefinite integral \int x^2 \sqrt{3 + x^3}dx. B.)Find the indefinite integral of the function \int (5 - s) \sqrt{s} ds. Integrate the following with respect...
Solve. 2x^2+3/x^2 (x-1) dx Solve: 2yy' = \frac{x}{(\sqrt{((x^2)-16)})} , y(5) = 2 Solve. 4x + y = 5\ 12x3y = 15 Solve y = x^{log_5(x)} then \frac{dy}{dx} = Solve. 4x - 3/5 = 2/5 Solve h(z) = z^4 cos z Solve 3/4 = 4/x. Solve. 8x...
【解析】 23.【精析 $$ \int _ { 0 } ^ { \frac { 1 } { 2 } } \frac { x } { \sqrt { 1 - x ^ { 2 } } } \arcsin r d x = - \int _ { 0 } ^ { \frac { 1 } { 2 } } \arcsin x d ( \sqrt { 1 - x ^ { 2 } } \\ = - \sqrt { ...
百度试题 结果1 题目(10)$$ \int \frac { \sqrt { x } } { \sqrt { x } - \sqrt [ 3 ] { x } } d x $$ 相关知识点: 试题来源: 解析 $$ 2 \times 7 $$ + 2 反馈 收藏
Answer to: Evaluate the integral: \int \frac{1}{\sqrt{x} - \sqrt[3]{x}} dx By signing up, you'll get thousands of step-by-step solutions to your...
Answer to: Evaluate the integral. \int \frac{x}{\sqrt{3x-1}}\,dx By signing up, you'll get thousands of step-by-step solutions to your homework...
int 3x^2 - 20x + 33 (2x + 1)(x - 2)^2 dx. 1. Evaluate the indefinite integral: \int \frac{1}{x^2\sqrt {9 - x^2 dx. 2. Evaluate the indefinite integral: \int \frac{5x + 3}{x^2 - 8x + 15} dx. Evaluate the integral: 1. \int (2x^4 + 3x^2 - 2x)dx ...