12.在△ABC中.已知a=$\frac{4\sqrt{3}}{3}$.b=4.A=30°.则△ABC的面积为$\frac{8}{3}\sqrt{3}$或$\frac{4}{3}\sqrt{3}$.
6.已知a.b.c分别是△ABC三个内角A.B.C的所对的边.且满足cosA+acosB=0.若a=4则△ABC的面积的最大值是$\frac{4\sqrt{3}}{3}$.
https://socratic.org/questions/how-do-you-simplify-4sqrt-3-sqrt12 1243=2 Explanation: 12=22⋅3=22⋅3=2⋅3 If a,b≥0 ... How do you simplify 5123 ? https://socratic.org/questions/how-do-you-simplify-5sqrt3-sqrt12 25 Explanation: [1] 1253 Rationalize the denom...
百度试题 结果1 题目\sqrt[3]{\frac{4}{3}}=___\sqrt{50}=___ 相关知识点: 试题来源: 解析 √[3](4/3);√(50) 反馈 收藏
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【解析】 15 答案: 5 3 5 3×5 5×5 15 5 结果四 题目 【题目】把√(4/3) 为最简二次根式,结果是 答案 【解析】11.(2√3)/3相关推荐 1【题目】把化为最简二次根式,结果是1-√2 2【题目】将化为最简二次根式结,果是 _ 3【题目】把化为最简二次根式结,果是 4【题目】...
解: \sqrt {4}=2,是整数,属于有理数; \frac {22}{7}是分数,属于有理数.在实数 \sqrt[3]{3}, \sqrt {4}, \frac {22}{7}, \frac {π}{2}中,无理数有 \sqrt[3]{3}和 \frac {π}{2}共2个.故选:B.无理数就是无限不循环小数.理解无理数的概念,一定要同时理解有理数...
D 解: \sqrt { \frac {4}{3}}= \sqrt { \frac {12}{9}}= \frac {2 \sqrt {3}}{3}.故选:D.原式化简得到结果,即可作出判断.此题考查了二次根式的性质与化简,熟练掌握二次根式的化简方法是解本题的关键.结果一 题目 【题文】化简 ,正确的是( )A.2 B. C.6 D. 答案 【...
11. 计算\sqrt{3}-\sqrt{\frac{4}{3}})\times \sqrt{15}=___ 相关知识点: 试题来源: 解析 √5 原式可化简为 (√3-(2√3)/3)* √(15),进一步计算得到 (√3)/3* √(15) = (√(45))/3 = (3√5)/3 = √5。因此,最终答案为 √5。反馈...
Evaluate {eq}\; \int \frac{4 + \sqrt{x}}{x^3} \, \mathrm{d}x {/eq}. Indefinite Integral: An indefinite integral is an integral without the lower and the upper limits. There is a set of rules to find the integral. We add an integration constant, C after finding the integral....