classSolution(object):defdecodeString(self, s):""" :type s: str :rtype: str """nums, chars = [], [] i, length =0,len(s)whilei < length: j = i +1ifs[i].isdigit(): num =int(s[i])whilej < length:ifs[j].isdigit():
题目地址:https://leetcode.com/problems/decode-string/description/ 题目描述 Given an encoded string, return it’s decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a...
class Solution { private int i = -1;//全局变量i,记录字符数组指针位置 public String decodeString(String s) { return dfs(s.toCharArray(), s.length()).toString(); } //递归函数 private StringBuilder dfs(char[] chars, int len) { int num = 0; StringBuilder str = new StringBuilder(); wh...
TinyURL is a URL shortening service where you enter a URL such ashttps://leetcode.com/problems/design-tinyurland it returns a short URL such ashttp://tinyurl.com/4e9iAk. Design the encode and decode methods for the TinyURL service. There is no restriction on how your encode/decode algori...
[Leetcode][python]Decode Ways/解码方法 题目大意 现在有如下的字母与数字的对应关系:1-A, 2-B, …26-Z。给定一个由数字组成的字符串,判断按照上面的映射可以转换成多少种不同的字符串。 解题思路 动态规划 参考:http://www.cnblogs.com/zuoyuan/p/3783897.html...
[Leetcode][python]Decode Ways/解码方法 题目大意 现在有如下的字母与数字的对应关系:1-A, 2-B, …26-Z。给定一个由数字组成的字符串,判断按照上面的映射可以转换成多少种不同的字符串。 解题思路 动态规划 参考:http://www.cnblogs.com/zuoyuan/p/3783897.html...
代码(Python3) class Solution: def decodeMessage(self, key: str, message: str) -> str: # 初始化对照表, '\0' 表示还未找到解密后的字母 chs: List[str] = ['\0'] * 26 # 初始化下一个加密字母对应的解密后的字母 origin: int = ord('a') # 遍历密钥中的每个字母 for ch in key: # ...
[Java/Python3/C++]栈:处理嵌套的编码内容【图解】 394. 字符串解码 题目 题目分析 思路分析 代码 题目给定一个经过编码的字符串,返回它解码后的字符串。编码规则为: k[encoded_string],表示其中方括号内部的 encoded_string 正好重复 k 次。注意 k 保证为正整数。你可以认为输入字符串总是有效的;输入字符串中...
[LeetCode] 34. Find First and Last Position of Element in Sorted Array 2019-11-04 12:18 −Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found i... ...
参考代码 1:Java Pythonpublic class Solution { public int numDecodings(String s) { int len = s.length(); if (len == 0) { return 0; } // dp[i] 以 s[i] 结尾的前缀子串有多少种解码方法 // dp[i] = dp[i - 1] * 1 if s[i] != '0' ...