题目地址:https://leetcode.com/problems/decode-string/description/ 题目描述 Given an encoded string, return it’s decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a...
https://leetcode-cn.com/problems/decode-string/ 给定一个经过编码的字符串,返回它解码后的字符串。 编码规则为: k[encoded_string],表示其中方括号内部的 encoded_string 正好重复 k 次。注意 k 保证为正整数。 你可以认为输入字符串总是有效的;输入字符串中没有额外的空格,且输入的方括号总是符合格式要求...
class Solution { private int i = -1;//全局变量i,记录字符数组指针位置 public String decodeString(String s) { return dfs(s.toCharArray(), s.length()).toString(); } //递归函数 private StringBuilder dfs(char[] chars, int len) { int num = 0; StringBuilder str = new StringBuilder(); wh...
publicclassSolution{publicStringdecodeString(String s){int n=s.length();Stack<Character>stack=newStack<Character>();String result="";String temp="";for(int i=0;i<n;i++){char str=s.charAt(i);if(str!=']'){stack.push(str);}else{char ch=stack.pop();while(ch!='['){temp=ch+tem...
代码(Python3) classSolution:defdecodeMessage(self,key:str,message:str)->str:# 初始化对照表, '\0' 表示还未找到解密后的字母chs:List[str]=['\0']*26# 初始化下一个加密字母对应的解密后的字母origin:int=ord('a')# 遍历密钥中的每个字母forchinkey:# 如果 ch 不是空格,且是第一次出现,则设置...
Given anon-emptystring containing only digits, determine the total number of ways to decode it. 这是一个dp问题。每次考虑s[1...k]所代表解码方式的可能性。第k个数字可能单独代表一个字母,或与前面一个数字组合成一个编码。 假如第k个数字是0,则不可能单独成为编码。假如第k-1个数字是1,则无论第k...
[LeetCode] 34. Find First and Last Position of Element in Sorted Array 2019-11-04 12:18 − Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found i... CNoodle 0 521 error Couldn't ...
Decode String 2019-12-21 15:05 − public class Solution { /** * @param s: an expression includes numbers, letters and brackets * @return: a string */ public String expres... YuriFLAG 0 230 leetcode 394. Decode String 2019-12-24 00:56 − 将一个带格式的字符串转换成一个...
classSolution(object):defnumDecodings(self,s):""" :type s: str :rtype: int """ifs[0]=='0':return0last_1=1last_2=1foriinrange(1,len(s)):ifs[i]=='0'and(s[i-1]!='1'ands[i-1]!='2'):return0ifint(s[i-1:i+1])<=26ands[i]!='0':tmp=last_2+last_1ifs[i]!=...
class Solution{private:intcount=0;map<int,string>m;public:// Encodes a URL to a shortened URL.stringencode(string longUrl){m[count]=longUrl;return"http://"+to_string(count++);}// Decodes a shortened URL to its original URL.stringdecode(string shortUrl){returnm[stol(shortUrl.substr(7...