*/classSolution{public:// 错误做法stringdecodeString(string s){if(s =="") {return""; } string result =""; stack<pair<char,int>> codes; codes.push({s[0],0});while(!codes.empty()) {autocontent = codes.top(); codes.pop();// 表明开始是数字if(content.first >='0'&& content.f...
题目地址:https://leetcode.com/problems/decode-string/description/ 题目描述 Given an encoded string, return it’s decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a...
<pre>publicclassSolution{/** * @param s an expression includes numbers, letters and brackets * @return a string */public StringexpressionExpand(String s){Stack<Object>stack=newStack<>();int number=0;for(char c:s.toCharArray()){if(Character.isDigit(c)){number=number*10+c-'0';}elseif(...
好久不用SplStack了。, 视频播放量 88、弹幕量 0、点赞数 0、投硬币枚数 0、收藏人数 0、转发人数 0, 视频作者 blackwoodkane, 作者简介 ,相关视频:LeetCode刷题日记 Day 14 Part 1 - Backspace String Compare,LeetCode刷题日记 Day 29 Part 1 - Longest Substring With
【Leetcode】394. Decode String 题目链接:https://leetcode.com/contest/3/problems/decode-string/ 题目: Given an encoded string, return it's decoded string. The encoding rule is:k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that...
class Solution { private int i = -1;//全局变量i,记录字符数组指针位置 public String decodeString(String s) { return dfs(s.toCharArray(), s.length()).toString(); } //递归函数 private StringBuilder dfs(char[] chars, int len) { int num = 0; StringBuilder str = new StringBuilder(); wh...
publicclassSolution{publicStringdecodeString(String s){returndecodeSub(s,1);}publicStringdecodeSub(String sub,int count){String trueStr="";for(int i=0;i<sub.length();i++){if(sub.charAt(i)-'1'>=0& .charAt(i)-'9'<=0){int subCount=sub.charAt(i)-'0';while(sub.charAt(i+1)-'...
题目的意思是:给你一个string,要求你按照规则解码这个string。 这是一个递归的解法。 首先如果是字母的话,我们就直接加入res中,如果不是,那就可能是数字,左中括号。 如果是数字,我们先计算出数字的值,数字之后必然是左中括号,然后我们跳过它,去递归解码左中括号里面的串,递归回来后。
leetcode394. Decode String 题目要求 Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer....
Solution encode的时候每次记录下每个String的长度,并记录入encode的结果中 decode的时候,根据每个String的长度来decode publicclassCodec{// Encodes a list of strings to a single string.publicStringencode(List<String>strs){StringBuffer out=newStringBuffer();for(String s:strs){out.append(s.length())....