https://leetcode.com/problems/decode-string/ https://leetcode.com/problems/decode-string/discuss/87728/share-my-c-solution https://leetcode.com/problems/decode-string/discuss/87543/0ms-simple-C%2B%2B-solution LeetCode All in One 题目讲解汇总(持续更新中...)...
Given an encoded string, return its decoded string. The encoding rule is:k[encoded_string], where theencoded_stringinside the square brackets is being repeated exactlyktimes. Note thatkis guaranteed to be a positive integer. You may assume that the input string is always valid; there are no ...
Given a string containing just the characters'(',')','{','}','['and']', determine if the input string is valid. 判断一个字符串中的括号是不是合法的。 题解:用栈做。 代码不贴了。 【22】Generate Parentheses(2019年1月22日,复习) 【28】Implement strStr()(算法群,2018年11月4日,练习kmp...
Output: “bacdfeg” Restrictions: The string consists of lower English letters only. Length of the given string and k will in the range [1, 10000] 本题题意十分简单,就是做一个字符串的反转,注意是没2k个子串中前k个反转,其余的不变 建议和leetcode 344. Reverse String 反转字符串 一起学习 代...
蓝桥杯关于字符串的算法题目(leetcode回文串的判断问题) 1.题目概述这个题目主要是需要我们找到回文串,这个回文实际上就是文学里面的这个修辞手法,在这个编程的时候:大概说的就是这个字符串从左向右个从右向左都是一样的这个效果,我们把这样的字符串成为回文串;不了解这个概念的可以去熟悉一下...,然后我们的这个...
Leetcode Solutions (0x6A73). Contribute to waffle87/leetcode development by creating an account on GitHub.
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: AI检测代码解析 s = "leetcode" return 0. s = "loveleetcode", return 2. 1. 2. 3. 4. 5. Note: You may assume the string contain only lowercase letter...
Decode and encode String 98Future关注IP属地: 湖北 2017.08.05 13:06:57字数0阅读144最后编辑于 :2017.12.09 21:21:04 ©著作权归作者所有,转载或内容合作请联系作者 0人点赞 Leetcode 更多精彩内容,就在简书APP "小礼物走一走,来简书关注我"赞赏支持还没有人赞赏,支持一下...
LeetCode 8 String to Integer (string转int) 题目来源:https://leetcode.com/problems/string-to-integer-atoi/ Implement atoi to convert a string to an integer. Hint: Carefully consider all possible input cases. If you want a challenge, please do not see below and ask yourself what are the ...
[LeetCode] 767. Reorganize String 重构字符串 Given a stringS, check if the letters can be rearranged so that two characters that are adjacent to each other are not the same. If possible, output any possible result. If not possible, return the empty string....