Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input:S ="leet2code3", K =10Output:"o"Explanation:The decodedstringis"leetleetcodeleetleetcodeleetleetcode". The10th letterinthestringis"o". Example 2: Input:S...
Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input: S ="leet2code3", K =10 Output:"o" Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". The 10th letter in the string is "o". ...
Now for some encoded string S, and an index K, find and return the K-th letter (1 indexed) in the decoded string. Example 1: Input: S = "leet2code3", K = 10 Output: "o" Explanation: The decoded string is "leetleetcodeleetleet...
Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: AI检测代码解析 Input: S = "leet2code3", K = 10 Output: "o" Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". The 10th letter in the...
<h2><a href="https://leetcode.com/problems/decoded-string-at-index">Decoded String at Index</a></h2> <img src='https://img.shields.io/badge/Difficulty-Medium-orange' alt='Difficulty: Medium' /><hr><p>You are given an encoded string <code>s</code>. To decode the string to a ...
DecodedStringAtIndex.java ExcelSheetColumnTitle.java GlobalAndLocalInversions.java LargestComponentSizebyCommonFactor.java MinimumIndexSumOfTwoLists.java NthDigit.java NthMagicalNumber.java ProjectionAreaOf3DShapes.java RangeAdditionII.java ReachingPoints.java ...
880.Decoded String at Index 思路 用size表示在i处,字符串进行解码后的长度。 如果有一个解码后的字符串为appleappleappleappleappleapple,且K=24,那么答案相当于在字符串apple中求K = 4的字符。即size=26,K=24的问题可转化为size=5,K=4的问题。 利用这一点可以先找到刚好size>=K的位置,再反向遍历S,不...
880.Decoded String at Index 思路 用size表示在i处,字符串进行解码后的长度。 如果有一个解码后的字符串为appleappleappleappleappleapple,且K=24,那么答案相当于在字符串apple中求K = 4的字符。即size=26,K=24的问题可转化为size=5,K=4的问题。
例如leet2code3可看为(leet*2,code)*3,K为10时,l为36,36/3 = 12,K%12 = 10,10比8(leetleet)长,那么直接返回10 - 8 = 2,即o。 class Solution { public: string decodeAtIndex(string S, int K) { string ans; string s; long l = 0; vector<pair<string, int>> seg; for (int i ...
leetcode 884. Decoded String at Indexd题解法 题目大意是给出编码之后的字符串,求解码后的字符串的指定位置的字符. 解题思路: (1)求解码后的字符串的长度. (2)回推出指定位置的字符. 代码如下: ...Decoded String at Index---emmm(没想到索引的好方法) 我这样写,最终会溢栈的,然后我也想了使用除余...