Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input:S ="leet2code3", K =10Output:"o"Explanation:The decodedstringis"leetleetcodeleetleetcodeleetleetcode". The10th letterinthestringis"o". Example 2: Input:S...
Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input: S ="leet2code3", K =10 Output:"o" Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". The 10th letter in the string is "o". ...
Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input: S = "leet2code3", K = 10 Output: "o" Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". The 10th letter in the string is "o...
<h2><a href="https://leetcode.com/problems/decoded-string-at-index">Decoded String at Index</a></h2> <img src='https://img.shields.io/badge/Difficulty-Medium-orange' alt='Difficulty: Medium' /><hr><p>You are given an encoded string <code>s</code>. To decode the string to a ...
DecodedStringAtIndex.java ExcelSheetColumnTitle.java GlobalAndLocalInversions.java LargestComponentSizebyCommonFactor.java MinimumIndexSumOfTwoLists.java NthDigit.java NthMagicalNumber.java ProjectionAreaOf3DShapes.java RangeAdditionII.java ReachingPoints.java ...
880.Decoded String at Index 思路用size表示在i处,字符串进行解码后的长度。 如果有一个解码后的字符串为appleappleappleappleappleapple,且K=24,那么答案相当于在字符串apple中求K = 4的字符。即size=26,K=24的问题可转化为size=5,K=4的问题。 利用这一点可以先找到刚好size>=K的位置,再反向遍历S,不断...
【LeetCode】880.DecodedString at Index 解题报告(Python) 【LeetCode】880.DecodedString at Index 解题报告(Python)标签(空格分隔): LeetCode作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/题目地址:https://leetcode.com/problems/decoded-... ...
880.Decoded String at Index 思路 用size表示在i处,字符串进行解码后的长度。 如果有一个解码后的字符串为appleappleappleappleappleapple,且K=24,那么答案相当于在字符串apple中求K = 4的字符。即size=26,K=24的问题可转化为size=5,K=4的问题。
参考[LeetCode] 880. Decoded String at Index 在位置坐标处解码字符串。 代码实现 Java classSolution{publicStringdecodeAtIndex(String S,intK){longsize=0;intindex=0;while(index < S.length() && size < K) {charc=S.charAt(index); size = Character.isDigit(c) ? size * (c -'0') : size...
Now for some encoded stringS, and an indexK, find and return theK-th letter (1 indexed) in the decoded string. Example 1: Input: S ="leet2code3", K =10 Output:"o" Explanation: The decoded string is "leetleetcodeleetleetcodeleetleetcode". ...