classSolution{public:stringdecodeAtIndex(stringS,intK){long size=0;// 要用long,如果用int会数据溢出int i=0;for(i=0;i<S.size();i++){if(!isdigit(S[i]))size++;elsesize*=S[i]-'0';if(size>=K)break;}if(i==S.size())// for循环时要注意越界问题i=S.size()-1;for(int j=i;j...
给你一个字符串,和一个数字k,求解密后的字符串的第index个字符。 解密规则: 读取字符串的每个字符,如果这个字符是字母,那么原样输出,如果是数字n,那么将已经遍历的所有字母再重复n-1遍。 二. 思路 代码: class Solution { public String decodeAtIndex(String str, int k) { long size =0 ; // step1:...
string decodeAtIndex(stringS,intK) { long cnt = 0; for (inti= 0;i<S.size(); ++i) { if (isalpha(S[i])) { if (++cnt==K) return string(1,S[i]); } else { if (cnt* (S[i] - '0') >=K) return decodeAtIndex(S.substr(0,i), (K- 1) % cnt + 1); cnt *= (S[...
参考[LeetCode] 880. Decoded String at Index 在位置坐标处解码字符串。 代码实现 Java classSolution{publicStringdecodeAtIndex(String S,intK){longsize=0;intindex=0;while(index < S.length() && size < K) {charc=S.charAt(index); size = Character.isDigit(c) ? size * (c -'0') : size ...
The decoded string is guaranteed to have less than2^63letters. class Solution { public String decodeAtIndex(String S, int K) { long curlength = 0; int n = S.length(); for(int i = 0; i < n; i++) { char c = S.charAt(i); ...
916-decoded-string-at-index/README.md +48 Original file line numberDiff line numberDiff line change @@ -0,0 +1,48 @@ 1 + Decoded String at Index You are given an encoded string s. To decode the string to a tape, the encoded string is read one character at a time and ...
DecodedStringAtIndex.java ExcelSheetColumnTitle.java GlobalAndLocalInversions.java LargestComponentSizebyCommonFactor.java MinimumIndexSumOfTwoLists.java NthDigit.java NthMagicalNumber.java ProjectionAreaOf3DShapes.java RangeAdditionII.java ReachingPoints.java ...
【LeetCode】880.DecodedString at Index 解题报告(Python)标签(空格分隔): LeetCode作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/题目地址:https://leetcode.com/problems/decoded-... 字符串 git 个人博客 原创 负雪明烛
880.Decoded String at Index 思路 用size表示在i处,字符串进行解码后的长度。 如果有一个解码后的字符串为appleappleappleappleappleapple,且K=24,那么答案相当于在字符串apple中求K = 4的字符。即size=26,K=24的问题可转化为size=5,K=4的问题。
Looking at the series as if they were indexed from the right side, converting N1 to the triangular number based on zero in the next-to-last position, and adding the index of N2 based on zero in the last position, gives us a series that descends from 9 to 0....