*/stringdecodeString3(string s){intlen = s.size();if(len ==0) {return""; }inti =0;returndecodeHelper(s, i); }stringdecodeHelper(string s,int& i){ string result ="";intlen = s.size();while(i < len && s[i] !=']') {// 非数字而是字符的情况下if(s[i] <'0'|| s[i...
题目链接:https://leetcode.com/contest/3/problems/decode-string/ 题目: Given an encoded string, return it's decoded string. The encoding rule is:k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note thatk You may assume that the inpu...
Given an encoded string, return its decoded string. The encoding rule is:k[encoded_string], where theencoded_stringinside the square brackets is being repeated exactlyktimes. Note thatkis guaranteed to be a positive integer. You may assume that the input string is always valid; there are no ...
* @return a string */public StringexpressionExpand(String s){Stack<Object>stack=newStack<>();int number=0;for(char c:s.toCharArray()){if(Character.isDigit(c)){number=number*10+c-'0';}elseif(c=='['){stack.push(Integer.valueOf(number));number=0;}elseif(c==']'){String newStr=...
LeetCode_394. Decode String 字符串解码 题目描述: 思路:首先想到使用栈来存放数据,一个数字栈,一个字符栈。 1.当遇到数字的时候就统计数字(注意数字可能会超过一位数) 2.当遇到字符的时候就记录下来 3.遇到’[‘时,就说明新的数字和字符串要开始了,需要将已经记录好的数字和字符串放到对应的堆栈当中...
Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer. ...
题目链接: Decode the Message: https://leetcode.com/problems/decode-the-message/ 无限集中的最小数字: https://leetcode.cn/problems/decode-the-message/ LeetCode 日更第189天,感谢阅读至此的你 欢迎点赞、收藏鼓励支持小满
若s[i−1]=="1"ors[i−1]=="2":此时,到当前位置的解码方法dp[i+1]和上上一位的相同,因为上一位和本位置结合在了一起。dp[i+1]=dp[i−1] 否则,返回0,表示无法解码 否则: 判断何时既可以自身解码也可以和前一位结合:若上一位s[i−1]=="1",则当前位既可以单独解码也可以和上一位结...
leetcode394. Decode String 题目要求 Given an encoded string, return it's decoded string. The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note that k is guaranteed to be a positive integer....
Given an encoded string, return its decoded string. 编码规则为: k[encoded_string],表示其中方括号内部的 encoded_string 正好重复 k 次。注意 k 保证为正整数。 The encoding rule is: k[encoded_string], where the encoded_string inside the square brackets is being repeated exactly k times. Note ...