Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before ...
buy and sell stocks 在leetcode现在总共有5 道题。 Best Time to Buy and Sell Stock 这道题是基础,只能transaction一次,所以我们用 Best Time to Buy and Sell Stock II 这道题表示可以一直transaction,所以只需要下一次比上一次高,那就加一次。 Best Time to Buy and Sell Stock with Cooldown 这道题属...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. Solution global(n, k) 表示前n天中一...
在【leetcode】714. Best Time to Buy and Sell Stock with Transaction Fee的基础上,dp[i][0] (跳过) 和dp[i][2]出售都是一样的,不同之处在于dp[i][1] ,这里有至少一天的CD,所以修改状态状态转移方程为:dp[i][1] = max(dp[i][1], -prices[i], dp[j][2] - prices[i]) (这里i > 2...
res+=tempreturnres 参考: 下面的更快,因为索引查找的次数少一些! classSolution(object):defmaxProfit(self, prices):""":type prices: List[int] :rtype: int"""iflen(prices) ==0:return0else: profit=0 start=prices[0]foriinrange(1,len(prices)):ifprices[i]>start: ...
Best time to buy and sell stocks IV 题目 https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit....
View Code 别人代码: View Code 学习之处: diff的变量命名不错 if(null==stocks || stocks.length==0) return 0; int maxProfit = 0 ; int cur = stocks[0]; for(int stock : stocks){ if(stock > cur) maxProfit += (stock-cur);
1.题目描述 Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the ...