Runtime: 68 ms, faster than 5.85% of Python3 online submissions for Best Time to Buy and Sell Stock II. Memory Usage: 14.2 MB, less than 5.06% of Python3 online submissions for Best Time to Buy and Sell Stock II. 所以想提高,还是要学一下迭代器的应用啊。 标签: python , LeetCode ...
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). ...
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). ...
Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in mul...
LeetCode 0122. Best Time to Buy and Sell Stock II买卖股票的最佳时机 II【Easy】【Python】【贪心】【动态规划】 Problem LeetCode Say you have an array for which theith element is the price of a given stock on dayi. Design an algorithm to find the maximum profit. You may complete as man...
Best Time to Buy and Sell Stock IV中是求某个给定k次交易的最大收益,和Maximum Subarray III完全一样 本题由于是可以操作任意次数,只为获得最大收益,而且对于一个上升子序列,比如:[5, 1, 2, 3, 4]中的1, 2, 3, 4序列来说,对于两种操作方案: 1 在1买入,4卖出 2 在1买入,2卖出同时买入,3卖出...
【leetcode】45-best-time-to-buy-and-sell-stock-with-cooldown 力扣 714. 买卖股票的最佳时机包含手续费 开源地址 为了便于大家学习,所有实现均已开源。欢迎 fork + star~ https://github.com/houbb/leetcode 121. 买卖股票的最佳时机 给定一个数组 prices ,它的第 i 个元素 prices[i] 表示一支给定股票第...
122. 买卖股票的最佳时机 II - 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天的价格。 在每一天,你可以决定是否购买和/或出售股票。你在任何时候 最多 只能持有 一股 股票。你也可以先购买,然后在 同一天 出售。 返回 你能获得的 最大 利润 。 示
122. 买卖股票的最佳时机 II - 给你一个整数数组 prices ,其中 prices[i] 表示某支股票第 i 天的价格。 在每一天,你可以决定是否购买和/或出售股票。你在任何时候 最多 只能持有 一股 股票。你也可以先购买,然后在 同一天 出售。 返回 你能获得的 最大 利润 。 示
// best-time-to-buy-and-sell-stock-2.cpp // Time:O(n), Space:O(1) #include <iostream> #include <vector> using namespace std; /* class Solution { public: int maxProfit(vector<int>& prices) { if (prices.size() == 0 || prices.size() == 1) return 0; ...