buy and sell stocks 在leetcode现在总共有5 道题。 Best Time to Buy and Sell Stock 这道题是基础,只能transaction一次,所以我们用 Best Time to Buy and Sell Stock II 这道题表示可以一直transaction,所以只需要下一次比上一次高,那就加一次。 Best Time to Buy and Sell Stock with Cooldown 这道题属...
Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. Note: You may not engage in multiple transactions at the same time (ie, you must sell the stock before ...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. Solution global(n, k) 表示前n天中一...
:rtype: int"""res=0foriinrange(1,len(prices)): temp= prices[i] - prices[i-1]iftemp <=0:continueelse: res+=tempreturnres 参考: 下面的更快,因为索引查找的次数少一些! classSolution(object):defmaxProfit(self, prices):""":type prices: List[int] :rtype: int"""iflen(prices) ==0:...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock-iv/ Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most k transactions. ...
Also you can't "short" a stock, you must buy before you sell the stock. Solution Let's think about a few things before we start coding. One thing to think about right off the bat is that we can't just find the maximum price and the lowest price and then subtract the two, because...
You may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again). 2.解法分析 限定了交易次数之后题目就需要我们略微思考一下了,由于有两次交易的机会,那么我们选定一个时间点ti,将此时间点作为两次交易的支点的话,必然有: ...