Say you have an array for which theithelement is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algor
right = 0, 1 # left=buy, right=sell maxP = 0 while right < len(prices): ## 遍历整个 list if prices[right] > prices[left]: ## 在存在赚钱机会的条件下 profit = prices[right] - prices[left] maxP = max(maxP, profit) else: ## 对于任意一个右指针日期,我们都要回顾它后面的所有...
输入:[7,6,4,3,1]输出:0解释: 在这种情况下, 没有交易完成, 所以最大利润为0。 解法: classSolution{public:intmaxProfit(vector<int>& prices){intsell =0;intbuy =0;if(prices.empty()){return0; }else{ buy = -prices[0]; }for(intprice : prices){ sell =max(sell, buy + price); buy...
https://leetcode.com/problems/best-time-to-buy-and-sell-stock/leetcode.com/problems/best-time-to-buy-and-sell-stock/ 解题思路 1. 暴力 O(n2) 复杂度,超时 class Solution { public: int maxProfit(vector<int>& prices) { int maxVal = 0; int n = prices.size(); for(int i = 0; ...
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
Leetcode: Best Time to Buy and Sell Stock 题目: Say you have an array for which the ith element is the price of a given stock on day i. If you were only permitted to complete at most one transaction (ie, buy one and sell one share of the stock), design an algorithm to find ...
Can you solve this real interview question? Best Time to Buy and Sell Stock - You are given an array prices where prices[i] is the price of a given stock on the ith day. You want to maximize your profit by choosing a single day to buy one stock and choo
Say you have an array for which theith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (i.e., buy one and sell one share of the stock), design an algorithm to find the maximum profit. ...
LeetCode 0121. Best Time to Buy and Sell Stock买卖股票的最佳时机【Easy】【Python】【贪心】 Problem LeetCode Say you have an array for which theith element is the price of a given stock on dayi. If you were only permitted to complete at most one transaction (i.e., buy one and sell...
最终的结果为sell2, 因为sell2包含了一次交易和二次交易的最大收益class Solution { public: int maxProfit(vector<int>& prices) { int n = prices.size(); int dp[n][2]; //vector 更耗时 memset(dp, 0, sizeof(dp)); int minv = prices[0], maxv = prices[n - 1], ans = 0...