问使用boost::asio将resolve_handler绑定到解析器async_resolveEN即使Boost.Asio可以异步处理任何类型的数据...
async_resolve(host, port,std::bind( &session::on_resolve, shared_from_this(), std::placeholders::_1, std::placeholders::_2)); } void on_resolve( boost::system::error_code ec, tcp::resolver::results_type results) { if(ec) { return fail(ec, "resolve"); } // Make the ...
sock.async_connect(*it, connect_handler); } } int main() { boost::asio::ip::tcp::resolver::query query("www.highscore.de", "80"); resolver.async_resolve(query, resolve_handler); io_service.run(); } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. ...
sock.async_connect(*it, connect_handler); } } int main() { boost::asio::ip::tcp::resolver::query query("www.highscore.de", "80"); resolver.async_resolve(query, resolve_handler); io_service.run(); } 这个程序最明显的部分是三个句柄的使用:connect_handler() 和 read_handler() 函数会...
endpoints) { asio::async_connect(socket_, endpoints, [this](std::error_code ec, ...
resolver的异步查询(async_resolve)让我搞了1个小时,虽然教程上说根据说明文档很容易使用async_resolve,但是实际编写时就遇到问题了。 bug:异步完成句柄被调用时始终传入error。 但从网上查资料,基本跟我写的一样啊,没什么区别。最后各种尝试,终于找出里面的原因来了。
auto point = co_await resolver.async_resolve("localhost", "8080", boost::asio::use_awaitable); co_await socket.async_connect( point->endpoint(), boost::asio::use_awaitable); 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. ws握手 ...
sock.async_receive(buffer(buff), on_read); 可以把下面列出来的类型都包装到一个buffer()方法中: • A char[] const array • A void* pointer and size in characters • An std::string string • An POD[] const array (POD stands for plain old data, meaning, constructor and destructor...
(30000))); tcp::resolver::iterator itrEndPoint = pClientResolver->resolve(*pClientResolverQuery); pCientSocket1->async_connect(*itrEndPoint, boost::bind(connect_handler, boost::asio::placeholders::error, pCientSocket1, pPeerSocket)); Sleep(2000); pPeerSocket->async_read_some(boost::asio:...
注意：这⾥的"出现"指的是streambuf的input sequence中出现，也就是如果原本streambuf中的内容已经符合条件，则async_read_until将⽴即呼叫回调。推论：某些库的until是不包含结束符的，⽐如readLine没有换⾏符。但是asio是包含的。using boost::system::error_code;// this piece of code shows how to ...