感谢http://fisherlei.blogspot.com/2013/11/leetcode-wordbreak-ii-solution.html的解释,我们可以加一个boolean的数组,b[i]表示从i到len的的字串可不可以进行word break. 如果我们在当前根本没有找到任何的word, 也就表明这一串是不能word break的,记一个false在数组里。这样下次进入dfs这里的时候,直接就返回一...
dict = ["cat", "cats", "and", "sand", "dog"]. A solution is ["cats and dog", "cat sand dog"].*/classSolution {public: vector<string> wordBreak(strings, unordered_set<string> &dict) { vector<string>retvec;if(s.size() ==0|| dict.size() ==0)returnretvec;intlen =s.size...
[leetcode] 140. Word Break II Description Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all su...[leetcode]140. Word Break II(Java) ......
题目链接:https://leetcode.com/problems/word-break-ii/ Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences. For example, given s = “catsanddog”, dict = [“cat”, “...
Can you solve this real interview question? Word Break II - Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note
Code Testcase Test Result Test Result 140. Word Break II Hard Topics Companies Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note that the same...
[LeetCode]140 Word Break II Solution{publicList<String>wordBreak(Strings,Set<String>dict){// Solution A:// return wordBreak_NP(s, dict);// Solution B:returnwordBreak_DP(s,dict);}/// Solution B: DP//publicList<String>wordBreak_DP(Strings,Set<String>dict){s="#"+s;intlen=s.length...
一到源自于 LeetCode 上的题,链接 Word Ladder II - LeetCodeleetcode.com/problems/word-ladder-ii/description/ 根据题意,要找到 beginWord 到 endWord 的所有变换路径,双向搜索的思路是:依次填充以 beginWord 和 endWord 为终点的两个有向图,当两个有向图出现共同单词时,以共同单词为连接点,连接两个有向...
{ endIndex = i break } } // 如果结束单词不在单词列表中,则无法转换,直接返回空列表 if endIndex == -1 { return nil } // 构建邻接表 adj := make(map[string][]int) for i, word := range wordList { // 枚举 word 替换的字符 for j := range word { // 将第 j 个字符替换为...
代码: importjava.util.ArrayList;importjava.util.Set;publicclassSolution{privateArrayList<String>resultList;privateArrayList<String>tmpList;publicArrayList<String>wordBreak(Strings,Set<String>dict){resultList=newArrayList();tmpList=newArrayList();divide(s,dict);returnresultList;}privatevoiddivide(Strings,Set...