2. Subsets II Given a collection of integers that might contain duplicates,nums, return all possible subsets (the power set). Note: The solution set must not contain duplicate subsets. For example, Ifnums=[1,2,2], a solution is: [ [2], [1], [1,2,2], [2,2], [1,2], [] ]...
Example2: Input: A= ["amazon","apple","facebook","google","leetcode"], B = ["l","e"] Output: ["apple","google","leetcode"] Example3: Input: A= ["amazon","apple","facebook","google","leetcode"], B = ["e","oo"] Output: ["facebook","google"] Example4: Input: A...
Input: A =["amazon","apple","facebook","google","leetcode"], B =["e","o"] Output:["facebook","google","leetcode"] Example 2: Input: A =["amazon","apple","facebook","google","leetcode"], B =["l","e"] Output:["apple","google","leetcode"] Example 3: Input: A =...
Example 4: Input:A = ["amazon","apple","facebook","google","leetcode"], B = ["lo","eo"] Output:["google","leetcode"] Example 5: Input:A = ["amazon","apple","facebook","google","leetcode"], B = ["ec","oc","ceo"] Output:["facebook","leetcode"] Note: 1 <= A....
classSolution{public:vector<string>wordSubsets(vector<string>& A, vector<string>& B){ vector<string> res;vector<int>charCnt(26);for(string &b : B) { vector<int> t =helper(b);for(inti =0; i <26; ++i) { charCnt[i] =max(charCnt[i], t[i]); ...
😏 LeetCode solutions in any programming language | 多种编程语言实现 LeetCode、《剑指 Offer(第 2 版)》、《程序员面试金典(第 6 版)》题解 - leetcode/solution/0900-0999/0916.Word Subsets/README.md at main · lei1024/leetcode
classSolution{publicList<String>wordSubsets(String[] A, String[] B){ List<String> ans =newArrayList<>();int[] cnt =newint[26];for(String word : B) {int[] tmp = letterCount(word);for(inti=0; i <26; i++) { cnt[i] = Math.max(cnt[i], tmp[i]); ...
Word Search - LeetCode 注意点 尽量减少函数参数的个数,而且最好使用引用,否则速度会慢很多 解法 解法一:典型的dfs。从开头的字母开始,往四周寻找下一个字母,如果没有匹配的就返回false。根据短路特性找到一个匹配的之后就会继续访问下去。 classSolution{public:booldfs(vector<vector<char>>& board,string& word...
题目:https://leetcode.com/contest/leetcode-weekly-contest-54/problems/partition-to-k-equal-sum-subsets/ 题意:给你一个数组和k,问能否将数组分为k组,且k组数的和相等 思路:记忆化搜索 代码: 状压dp(贴个官方题解的):...猜你喜欢LintCode 691. Recover Binary Search Tree Recover Binary Search ...
word ="ABCB", -> returnsfalse. 需要尝试从每一个位置起开始遍历,每次向四个方向开始遍历,如果四个方向都不满足时要将走过的路径回复,边界问题看代码: 用一个index记录查了多少个了。 迭代算法依然没有知道突破口: 1publicclassSolution {2privateintm,n;3publicbooleanexist(char[][] board, String word) ...