LeetCode -- Word Break 动态规划,详细理解 Given a stringsand a dictionary of wordsdict, determine ifscan be segmented into a space-separated sequence of one or more dictionary words. For example, given s="leetcode", dict=["leet", "code"]. Return true because"leetcode"can be segmented as...
s="leetcode", dict=["leet", "code"]. Return true because"leetcode"can be segmented as"leet code". 地址:https://oj.leetcode.com/problems/word-break/ 算法:显然,这一道动态规划的题目。用数组dp来存储每一个子问题,其中dp[i]表示在从0到i(包括i)的字串是否能够由字典组成。那么dp[i+1]的解...
Can you solve this real interview question? Word Break II - Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note
1. public boolean wordBreak(String s, Set<String> wordDict) { 2. boolean res[] = new boolean[s.length() + 1];// 表示到i为止的子串能否用单词表示 3. 0] = true; 4. for (int i = 0; i <= s.length(); i++) { 5. for (int j = 0; j < i; j++) { 6. if (res[j]...
140. Word Break II Hard Topics Companies Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note that the same word in the dictionary may be reused...
【Leetcode】Word Break II 题目链接:https://leetcode.com/problems/word-break-ii/ Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences....
Return true because "leetcode" can be segmented as "leet code". ** My code: importjava.util.Set;publicclassSolution{publicbooleanwordBreak(Strings,Set<String>wordDict){boolean[]isBreakUp=newboolean[s.length()+1];isBreakUp[0]=true;for(inti=1;i<s.length()+1;i++){for(intj=0;j<i;j...
参考了Discuss区一个DFS+DP的解法(https://leetcode.com/problems/word-break-ii/discuss/44262/My-C%2B%2B-DP%2BDFS-solution-(4ms)),学到了一种新的剪枝策略: classSolution{private://DFS path build functionvoidbuildPath(boolisBreakable[],string&s,intpos,vector<string>&res,string curP,unordered_...
2019-12-06 08:07 − 原题链接在这里:https://leetcode.com/problems/word-subsets/ 题目: We are given two arrays A and B of words. Each word is a string of lo... Dylan_Java_NYC 0 358 Leetcode solution 243: Shortest Word Distance 2019-12-26 03:41 − Problem Statement Given...
https://leetcode.com/problems/word-ladder/description/ Problem: Given two words (beginWord and endWord), and a dictionary’s word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word mus...