Word Break - LeetCode Given a stringsand a dictionary of wordsdict, determine ifscan be segmented into a space-separated sequence of one or more dictionary words. For example, given s="leetcode", dict=["leet", "code"]. Return true because"leetcode"can be segmented as"leet code". 思路...
dp[0] =true;for(inti =1; i < len+1; i++){for(intk =0; k < i; k++){if(dp[k] && wordDict.find(s.substr(k,i-k)) !=wordDict.end()){ dp[i]=true;break;//break是因为题目只是需要判断是否存在 } } }returndp[len]; } }; II https://leetcode.com/problems/word-break-i...
public boolean wordBreak(String s, Set<String> wordDict) { boolean[] dp = new boolean[s.length()+1]; Arrays.fill(dp,false); dp[s.length()]=true; // 外层循环递增长度 for(int i = s.length()-1; i >=0 ; i--){ // 内层循环寻找分割点 for(int j = i; j < s.length(); ...
publicbooleanwordBreak(Strings,Set<String>dict){intlen=s.length();boolean[]dp=newboolean[len+1];dp[0]=true;// 当前字符串:0~ifor(inti=1;i<=len;i++){// 将当前的字符串再进行拆分,查看它是否包含在 dict 中for(intj=0;j<i;j++){// dp[j] 是前面已经计算出来的结果if(dp[j]&&dict....
【Leetcode】Word Break 题目链接:https://leetcode.com/problems/word-break/ 题目: Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, given...
Leetcode: Word Break Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, given s ="leetcode", dict =["leet","code"].
Can you solve this real interview question? Word Break II - Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note
Can you solve this real interview question? Word Break II - Given a string s and a dictionary of strings wordDict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all such possible sentences in any order. Note
[leetcode] 140. Word Break II Description Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all su...[leetcode]140. Word Break II(Java) ......
139. Word Breakwindliang 互联网行业 开发工程师 来自专栏 · LeetCode刷题 1 人赞同了该文章 题目描述(中等难度) 给一个字符串,和一些单词,问字符串能不能由这些单词构成。每个单词可以用多次,也可以不用。 解法一 回溯 来一个简单粗暴的方法,利用回溯法,用 wordDict 去生成所有可能的字符串。