正切函数的诱导公式 (1)$$ \tan ( 2 \pi + \alpha ) = \tan \alpha $$ ;(2)$$ \tan ( - \alpha ) = - \tan \alpha $$ (3)$$ \tan ( 2 \pi - \alpha ) = - \tan \alpha $$ (4)$$ \tan ( \pi - \alpha ) = - \tan \alpha $$;(5)$$ \tan ( \pi + ...
百度试题 结果1 题目 (3)公式$$ \tan ( \pi + \alpha ) = \tan \alpha $$中,$$ \alpha = \frac { \pi } { 2 } $$不成立. ( ✓ ) 相关知识点: 试题来源: 解析 答案见上 反馈 收藏
若tanα=3,则tan(α+π/4)=( )。 A.2B.1/2 C.-2D.-4 点击查看答案手机看题 你可能感兴趣的试题 单项选择题 下列函数中,为偶函教的是( )。 A. y=log2xB. y=X2+XC. y=4/xD. y=x2 点击查看答案手机看题 单项选择题 将一颗骰子抛掷1次,则得到的点教为偶数的概率为( )。 A.2/3...
在\displaystyle(2k\pi-\frac{\pi}{2},2k\pi+\frac{\pi}{2})(k\in Z)上单调递增; 在\displaystyle(2k\pi+\frac{\pi}{2},2k\pi+\frac{3\pi}{2})(k\in Z)上单调递减。 ⑥最值: 当\displaystyle x=2k\pi+\frac{\pi}{2}时,\displaystyle y_{max}=1; 当\displaystyle x=2k\pi+\frac...
Q08 (2S)-2-(2-{[7-Chloro-6-[(6,7-dimethoxy-3,4-dihydroisoquinolin-2(1H)-yl)carbonyl]-3-(3,5-dimethylphenyl)-2-oxo-1,2-dihydroquinolin-4-yl]oxy}ethyl)piperidinium trifluoroacetate 186 N10K, T32I, R262Q, Y284C COS-7 96 A-177775 3′-N-Desmethyl-3′-N-cyclopentyl-11-deox...
10.解析:由$$ \tan ( \pi - \alpha ) = - \frac { 2 } { 3 } $$,得$$ \tan \alpha = \frac { 2 } { 3 } $$,则$$ \frac { \cos ( - \alpha ) + 3 \sin ( \pi + \alpha ) } { \cos ( \pi - \alpha ) + 9 \sin \alpha } $$ $$ = \frac { ...
解析 【解析】 $$ \sin \alpha \cos ( \pi + \alpha ) \tan ( - \pi - \alpha ) = \sin \alpha ( - \cos \alpha ) $$ $$ ( - \tan \alpha ) = \sin ^ { 2 } \alpha \cdot $$ 故答案为: $$ \sin ^ { 2 } $$α ...
1、首先你的这个公式是错的。应该为：360*cos(delta)/(4*z) -180*tan(alpha)/pi-alpha 2、360*cos(delta)/(4*z)：这一部分为单个轮齿的一半对应的圆心角（分度圆）3、180*tan(alpha)/pi-alpha为渐开线的展角，教科书上一般是弧度制展角θ=tanα/-α。4、这是锥齿轮当量齿轮展开后，...
This definition of π implicitly makes use of flat (Euclidean) geometry; although the notion of a circle can be extended to any curve (non-Euclidean) geometry, these new circles will no longer satisfy the formula textstylepi=fracCd. Here, the circumference of a circle is the arc length ...
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