2. \frac{4}{5}. 1. 解法一: 由于\frac{ \pi }{2}<{}\alpha < {} \pi ,\tan \alpha -\cot \alpha =-\frac{8}{3}, 则有3{{\tan }^{2}}\alpha +8\tan \alpha -3=0, 解得\tan \alpha =\frac{1}{3}或\tan \alpha =-3, 因为\frac{ \pi }{2}<{}\alpha < {...
Step by step video, text & image solution for If u=cot^-1 sqrt(tanalpha)-tan^-1 sqrt(tan alpha), then tan(pi/4-u/2) is equal to (a) sqrt(tan alpha) (b) sqrt(cos alpha) (c) tan alpha (d) cot alpha by Maths experts to help you in doubts & scoring excellent marks in ...
结果1 结果2 题目 2.化简: \$\frac { \cos ( 2 \pi - \alpha ) \cot ( \pi + \alpha ) \tan ( - \alpha - \pi ) } { \sin ( \pi - \alpha ) \cot ( 3 \pi - \alpha ) }\$ 相关知识点: 试题来源: 解析2.13 _
【解析】证明: 【解析】证明: (1) \$\frac { \sin ( 2 \pi - \alpha ) \tan ( \pi + \alpha ) \cot ( - \alpha - \pi ) } { \cos ( \pi - \alpha ) \tan ( 3 \pi - \alpha ) }\$ \$= \frac { \sin ( - \alpha ) \tan \alpha \cot ( - \alpha ) ...
【解析】 【解析】 证明: \$\frac { \sin ( 2 \pi - \alpha ) \tan ( 5 \pi + \alpha ) \cot ( - \alpha - \pi ) } { \cos ( \pi - \alpha ) \tan ( - \alpha ) }\$ \$= \frac { - \sin \alpha \cdot \tan ( \pi + \alpha ) \cot [ - ( \pi + \alph...
⎛⎜⎜⎝1+sin2αcos(2α−2π)tan(α−3π4)⎞⎟⎟⎠−14sin2α(cot(α2)+cot(3π2+α2) simplifies and reduces to Video Solution | ShareSave Answer Step by step video & image solution for ((1+sin2alpha)/(cos(2alpha-2pi)tan(alpha-(3pi)/4)))-1/4sin2alpha(...