这两段区间包括2在内的所有subarray的最小值都是2,其分别可以组成的subarry的个数是 len([3])和len([4,5]),左右区间合并在一起可以组成的subarray的个数是len([3])*len([4,5]),再加上2本身自己组成一个独立的subarray [2],其总数就是 len([3]) + len([4,5]) + len([3])*len([4,5]
Can you solve this real interview question? Sum of Subarray Minimums - Given an array of integers arr, find the sum of min(b), where b ranges over every (contiguous) subarray of arr. Since the answer may be large, return the answer modulo 109 + 7. Ex
Given an array of integers arr, find the sum ofmin(b), wherebranges over every (contiguous) subarray ofarr. Since the answer may be large, return the answer modulo109 + 7. Example 1: Input:arr = [3,1,2,4]Output:17Explanation:Subarrays are [3], [1], [2], [4], [3,1], [...
It is likely that we'll consider the O(n^2) solution optimal since we are adding O(n^2) numbers. But if we jump out of the box of "adding number one at a time", we'll see a O(n) solution. For each array element A[i], if we can find out how many subarrays have it as...
[LeetCode] Sum of Subarray Minimums Description Sum of Subarray Minimums: Given an array of integers arr, find the sum of min(b), where b ranges over every (contiguous) subarray of arr. Since the answer may be large, return the answer m......
https://leetcode.com/problems/sum-of-subarray-minimums/discuss/178876/stack-solution-with-very-detailed-explanation-step-by-step classSolution {publicintsumSubarrayMins(int[] A) {intlen =A.length; Stack<Integer> stack =newStack<>();int[] left =newint[len];int[] right =newint[len];for...
907. Sum of Subarray Minimums Given an array of integers A, find the sum of min(B), where B ranges over every (contiguous) subarray of A. Since the answer may be large, return the answer modulo 10^9 + 7.Example 1: Input: [3,1,2,4] Output: 17 Explanation: Subarrays are [3]...
907. Sum of Subarray Minimums Given an array of integers A, find the sum of min(B), where B ranges over every (contiguous) subarray of A. Since the answer may be large, return the answer modulo 10^9 + 7....
No.907 Sum of Subarray Minimums,907.子数组的最小值之和-力扣(LeetCode)(leetcode-cn.com)思路参考:【LeetCode】907.SumofSubarrayMinimums_哔哩哔哩_bilibili做过较多类似题目的话很容易就想到枚举每个数字将其作为最小数时计算其所包含的子数组个数,...
907. Sum of Subarray Minimums 难度:m class Solution: def sumSubarrayMins(self, A: List[int]) -> int: res = 0 stack = [] for i, n in enumerate(A): while stack and A[stack[-1][0]] >= n: stack.pop() if stack: si = n*(i-stack[-1][0])+stack[-1][1] ...